2NaCl + F2 -> 2NaF + Cl2
The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
The balanced equation is as follows:
F2 + 2NaCl --> 2NaF + Cl2
Cl2 + 2NaBr -> 2NaCl + Br2
NaCl is already balanced. Na+ and Cl- make NaCl.
The reqctin is (electrolysis of molten sodium chlorie);
2 NaCl = 2 Na + Cl2
That is not a chemical equation.
By writing 2 Na + F2 -> 2 NaF.
2 NaClO3 = 2 NaCl + 3 O2
2NaCl + F2 -- 2NaF + Cl2
2 Na + F2 --> 2 NaF It is one of the most violent reactions between two elements.
The formula is K3N. The name of the compound is potassium nitride.
Na+F form NaF a ionic compound
The intermolecular forces holding F2 molecules together are relatively weak in comparison to the forces binding NaF molecules.
2NaCl + F2 -- 2NaF + Cl2
Yes
2 Na + F2 --> 2 NaF It is one of the most violent reactions between two elements.
It is a REDOX reaction. Sodium is oxidized by Fluorine which is itself reduced by the sodium. 2Na + F2 = 2NaF.
Flourine has a charge of -1 and sodium has a charge of +1. Together they are equivalent to 0, so they are already perfectly balanced. An empirical formula is just a way to express the "smallest" balanced ratio. and since you can't get any smaller or more basic than 1 NA and 1 F, your empirical formula is just that: NaF.
No.for a start you have potassium on one side (K) and sodium on the other (Na) and what has happened to the Oxygen (O).Your chemical equation does not make any sense.
The chemical equation is:MgF2 + 2 Na = 2 NaF
F2 + 2 NaCl = 2 NaF + Cl2
Yes it will form ionic bond (as in NaF or MgF2) or covalent bond as in F2 or ClF3)
Sodium (Na), and fluorine (F) combine to form sodium fluoride (NaF).
The reaction i the following:2 NaCl + F2 = 2 NaF + Cl2
To find percent composition, you must work with the atomic masses. Look on a periodic chart to find the atomic masses of F and Na. You will find that Na has an atomic mass of 22.990 grams per mole of Na and that F has an atomic mass of 18.998 grams per mole of F. So, add these both together, and that will tell you how much mass NaF will be. NaF will have a mass of 41.988 grams per mole of NaF. Now to take the percent composition of F in NaF, simply divide the mass of F by the mass of NaF. That will give you [18.998/41.988]=.452 which will be about 45%. So your answer is that F has a 45% composition of NaF. PS: Since Na and F only had a stoichiometry of 1 (meaning there is 1 Na and 1 F in the molecule), no multiplication of the atomic masses was necessary when calculating the total mass of the molecule.