F2(g) + 2NaI ---> 2IF + 2Na
Produces Sodium chloride and Iodine
Pb(C2H3O2)2 + NaI * All numbers should be at the lower right corner.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
2F2 + 4NaOH >> 4NaF + O2 + 2H2O
KI + NaCl = KCl + NaI
The answer for Sodium Iodide is NaI
yes..no
NH4I + NaOH -> NH4+ + I- + Na+ + OH- -> NH3 + H2O +I- + Na+
No, reaction
Produces Sodium chloride and Iodine
The reaction i the following:2 NaCl + F2 = 2 NaF + Cl2
Pb(C2H3O2)2 + NaI * All numbers should be at the lower right corner.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
RbF
Sodium Iodide is the solute which is created in the reaction and Sodium actetate solution is created. NaI + PbC2H3O2 ---> PbI (Plumbum Iodide) + NaC2H3O2 (Sodium Acetate) solution.
NaI is sodium iodide
2F2 + 4NaOH >> 4NaF + O2 + 2H2O