Pb(C2H3O2)2 + NaI * All numbers should be at the lower right corner.
Produces yellow Lead(II) iodide and Sodium nitrate
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Lead acetate's chemical formula is Pb(CH3COO)2
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
Lead(II) iodide and Sodium nitrate
Produces yellow Lead(II) iodide and Sodium nitrate
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
A precipitate of yellow Lead iodide and Sodium nitrate are formed
CH3COO4- (C2H3O5-) is the chemical formula of the 2-hydroperoxy-2-hydroxy-acetate anion. Of course if the 4 was a typo for H it would be acetic acid. If there are brackets (CH3COO)4 its the tetracacetate portion of the formula of a salt such as lead(IV) acetate.
The weight will approximately be 950 grams. YOUR WELCOME.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Lead acetate's chemical formula is Pb(CH3COO)2
Take a few drops of both samples and add some lead nitrate. A yellow precipitate indicates lead iodide and it gives the inference that it contains iodide ions, hence the solution of sodium iodide.
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
The chemical formula of lead acetate is Pb(CH3COO)4.
PbI2