The weight will approximately be 950 grams.
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To prepare 160 grams of potassium acetate with a 5% w/w concentration, you would need to calculate the mass of the potassium acetate in the solution. Since the concentration is given as a percentage by weight, 5% of 160 grams is 8 grams of potassium acetate. The remaining mass in the solution would be water. Therefore, you would need 152 grams of water to prepare 160 grams of potassium acetate with a 5% w/w concentration.
3% = 3 g solute / 100 g water So, for 200 g water, you will need 2X3 g = 6 grams potassium iodide This assumes that what's meant is "weight percent", sometimes abbreviated as "w/w %" or "wt %". It would be highly unusual for a chemist to specify the concentration as a percent.
Potassium iodide is not added to sodium chloride. Potassium iodide is a compound made up of potassium and iodine, while sodium chloride is made up of sodium and chloride ions. They are two different compounds and do not typically react together to form a new compound.
Iodized salt is not an element. It is a mixture of at least two compounds:sodium chloride (roughly 99.9% by weight), these are cubic shaped crystals.sodium iodide (roughly 0.1% by weight), these are elongated prism shaped crystals.it may also include other salts like potassium chloride, potassium iodide, sodium bromide, etc. in small amounts
The molecular weight of sodium acetate is 82.03 g/mol.
i think Megestrol acetate is for reverse weight
The equivalent weight of zinc acetate is 136 g/mol.
- The atomic weight of iodine is 126,90447; for a 0,1 N solution, dividing by 10 the result is 12,69. - The iodide (KI) is added to increase the solubility of iodine in water or alcohol.
The formula for sodium acetate is CH3COONa and the equivalent weight is the same as the molecular weight (molar mass) which is 82.0343 g/mol.
We have 495 ml, but we need to convert this to 1000, so we divide by 495 and multiply by 1000. We also do this to 21.1g. 21.1/495*100 is 42.626g. KI's molecular weight is 166g/mol. 42.626/166 is 0.2568 molar.
The theoretical oxygen demand (ThOD) of acetate is 2 moles of O₂ per mole of acetate. To calculate the ThOD of a 1mM acetate solution, you would convert mM to moles (1 mM = 0.001 moles) and then multiply by the ThOD (2 moles O₂/mole acetate) to get 0.002 moles of O₂.
Zeisel's method is used to estimate the alkoxy linkages in an organic compound. In this method the organic compound containing alkoxy group is treated with hydrogen iodide and the alkyl halide formed is further treated with silver nitrate to precipitate silver iodide In this reaction only hydrogen iodide can be used because it consists of an ionic bond, while HF, HCl, HBr contain covalent bond where an iodide ion is liberated which forms a precipitate with silver nitrate. The silver iodide can be weighed and from its weight the number or alkoxy group can be estimated.