MCF * BTU = MMBTU
MMBTU * KWH = Heat rate
Divide heat added to the boiler between feedwater inlet and steam outlet by the kilowatt output of the generator at the generator terminals. Rate expressed in btu. See article.
212 degrees Fahrenheit
manish
There are many factors. First of all, there is the temperature of the water. Next, the is the volume of water. Next there is the amount of pressure gradually built up in the boiler. Next you have the amount and speed at which heat is transferred to the water.
E=MC2 + o2 + H20 = Heat rate
because of heat transfer rate is better
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Heat flux is the primary performance paramater in boiler performance. Heat flux can be affected by many factors espacially by boiler tube fouling ( or exchange surfaces) that will considerably reduce heat exchange.
I would recommend using a double boiler. If a double boiler is unavailable, I would heat it on low heat and stir it frequently.
Efficiency = (860.4*100)/(Heat rate in kCal/kWh) or Efficiency = (860.4*4.18*100)/(Heat rate in kJ/kWh) Ex 1: if heat rate is 2500 kCal/kWh, then efficiency is 34.416% Ex 2: if heat rate is 9000 kJ/kWh, then efficiency is 39.96%