There are three formulas to calculate current. They are I = E/R, I = W/E and I = the sq. root of W/R. As you can see there is one value missing in your question so it can not be answered.
aA A: the output of a Bridger's rectifier will always follows proportionally to the load since it does not regulate the output it merely transform AC TO DC '
we should be take two point from the the graph between collector current and emitter-collector voltage.. along the horizontal line collector current is zero and emitter-collector voltage become Vcc,and along the vertical line emitter-collector voltage is zero and collector current become Vcc/RL then by this line that drow between this two point is called load line that in this line the transistor allowed to operate....
Amp measurement in a dc circuit is commonly done by use of a clamp on amp meter. The meter has a loop on one end that opens up. The loop is clamped around a wire, and the meter shows the amperage.
RMS current is converted to DC current by using a rectifier. Capacitors and other components are used to make a cleaner DC output with less ripple.
I would assume that you mean what devices do you use to convert ac current to dc current?The answer is Diodes.seediode-bridge
DC Current divided by 1.225
Summation of individual load connected on the board gives the total load. Power (Load ) = Voltage x rated current.
A: A transistor has voltage gain as base current is allow to flow. If the load is constant then a DC mirror azimuth path can be plotted as a function of base current and collector current and that is the load line
for DC load and if its copper wire the cross section of the conductor wire is generally calculated as 1/4 th of the current rating . Eg for a DC load of 16 amp the copper conductor with 4 mm square is selected.
The terms a.c. and d.c. stand for alternating current and direct current, respectively.
WHEN YOU STEP UP THE VOLTAGE AND THE LOAD IS THE SAME MORE CURRENT WILL FLOW NOT LESS. AND THAT WILL HOLD TRUE FOR DC AS WELL. IF THE LOAD REMAINS THE SAME AND YOU INCREASE THE CURRENT AC OR DC THE VOLTAGE WILL INCREASE
I am not an electrical guy....but since this question was left unanswered....i'll just put in some nonsense!! For AC Load: VxIxPF (V=VoltageRequired, I=Current Required, PF=Power Factor) The Power Factor is normally considered to be 0.8 as a thumb rule. For DC Load: VxI, here the power factor is consisdered to be 1, since it is a DC current !! Byeee!
The reason an AC voltage applied across a load resistance produces alternating current is because when you have AC voltage you have to have AC current. If DC voltage is applied, DC current is produced.
The source current is that current which will leave the DC regulator and travel to the load circuit connected to it. The sink current is that current which may come from the load circuit and attempt to find a path through the ground through the regulator. Generally most regulators are designed to just source current to a load and are not setup to receive current back(sink it)
without knowing load, cannot say
It depends on the total load of the transistor as to what the shape of the slope is for the DC load line. A transistor gains voltage as base current is allowed to flow.
Direct Current (DC) is an electric current flowing in one direction only.For the source and more detailed information concerning this subject, click on the related links section indicated below.