You need a graphic concentration versus absorbance.
32mg/dl = brix
2B)
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
25 ml added to 95 ml give a final volume of 120 ml (95 ml)(1.4 M) = (120 ml)(x M) x = 1.1 M
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
You cannot.
You need a graphic concentration versus absorbance.
32mg/dl = brix
This is the concentration of the ion H+.
2B)
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
No. That's only one of several possibilities. -- with initial velocity, distance, and time, you can calculate acceleration -- with final velocity, distance, and time, you can calculate acceleration -- with force and mass, you can calculate acceleration -- with initial and final momentum, you can calculate acceleration -- with initial and final kinetic energy, you can calculate acceleration -- with mass, velocity at either end, and kinetic energy at the other end, you can calculate acceleration And I'm sure there are several more that I've missed.
25 ml added to 95 ml give a final volume of 120 ml (95 ml)(1.4 M) = (120 ml)(x M) x = 1.1 M
v1= initial volume c1= initial concentration v2= final volume c2= final concentration For example, you have 10mL of an unknown substance with a concentration of 0,5mol/L. If you add 50mL, what will the final concentration be. V1= 10mL C1= 0,5mol/L V2= 60mL C2= x 10/0,5=60/x You must start by putting everything in the same mesure. We'll use mL here. So 0,5-->1000mL= 50-->10mL 50x60= 300 300/10= 30 30 is your C2
How to work it out - Calculate the concentration of the solution in terms of molarity. Calculate the hydrogen ion concentration from the fact that multiplying the hydrogen and hydroxide concentrations (in mols per litre) will always give 1x10-14. Take the -log10 of the hydrogen ion concentration.
Depending on its concentration you can calculate it by this formula: pH = -log[H3O+]