25 ml added to 95 ml give a final volume of 120 ml (95 ml)(1.4 M) = (120 ml)(x M)
x = 1.1 M
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
13.6% methanol solution.
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
4ml/1000 = approx 4000 ppm, depending on the final volume after adding 4ml to 1000 ml water
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
Adding more solvent to a solution decreases the molarity of the solution. This is based on the principle that initial volume times initial molarity must be equivalent to final volume times final molarity.
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
Depending on the volume of water ! For 1 L, the molarity is approx. 0,1.
4.0%
13.6% methanol solution.
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
4ml/1000 = approx 4000 ppm, depending on the final volume after adding 4ml to 1000 ml water
Use the equation M(initial)*V(initial)=M(final)*V(final). In this case, M(initial) is 0.200 M NaCl. V(initial) is 20.0mL. V(final) is 250.0mL. You are solving for M(final). To solve, you rearrange the equation so M(final)=(M(initial)*V(initial))/V(final), which gives you (0.200*20.0)/250. The answer is 0.016 M for M(final). You don't need to convert mL to L in this type of problem. You can if you want, but you will end up with the same answer. It's just an extra unnecessary step, unless the question is asking for a Volume in L. But in this case you were asked for concentration (Molarity), so no volume conversions were necessary.
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
We must first figure out the amount of NaCl in moles: M = mol/L = mmol/mL 6 = mmol/25 mL 150 mmol NaCl Now divide by the total volume to get the final concentration: 150 mmol/100 mL = 1.5 M NaCl