For lamps in parallel, it's straightforward, as you only need to add the individual power ratings to find the total power rating and multiply this value for the time over which they operate, to determine the energy dissipation.
For lamps in parallel, it's far more complicated. Lamps in parallel are not subject to their rated voltages and, so, cannot operate at their rated powers. In fact, the lamp with the lowest power rating will actually burn the brightest! Trying to calculate what is going on is further complicated by the fact that there is significant difference in the resistance of a lamp when it is operating at its operating temperature and when it is cold, and you cannot determine these resistances theoretically. So, while you can determine the answer to your question experimentally -by measuring the current and voltage- it is not practical to calculate the answer you are looking for.
In simple way resistor bank contains number of resistors in series or parallel combination. They are connected in parallel to decrease the resistance and increase current rating and power dissipation.And they are connected in series to increase resistance and power dissipation.
Home devices are connected in parallel and not in series.
It is not necessary for anything about them to be the same.All that is necessary is that they create the desired equivalent resistor, having the correct resistance and power dissipation rating without overstressing either resistor.
They are not. They are connected differently, and the voltages and currents behave in different ways.
A voltmeter can be connected in parallel with a resistor to show the voltage across the resistor.
In simple way resistor bank contains number of resistors in series or parallel combination. They are connected in parallel to decrease the resistance and increase current rating and power dissipation.And they are connected in series to increase resistance and power dissipation.
ameter has a low resistance so if it is placed in parallel with the load then it will experiance voltage as much as the load and according to equation power=v2/r the power will be very high as high v or low r both favors for a high power dissipation . but on a series combination most of the voltage drop will be on load the ameter will not have a high power dissipation
Power dissipation in a resistor, or any other type of load, for that matter, is measured in watts and calculated as volts times amperes. It does not matter if the resistor is in a series or a parallel circuit, so long as the volts and amperes in the calculation is for that one resistor. Obviously, volts and amperes is distributed amongst the components of a circuit, and series vs parallel can have a significant affect on that distribution, so you will need to calculate or measure them on a case by case basis.
Resistance is connected in parallel with voltmeter or say, voltmeter is connected in parallel with resistance.
Components connected in series are connected along a single path, so the same current flows through all of the components.Components connected in parallel are connected so the same voltage is applied to each component
All home appliances are connected in parallel.
Home devices are connected in parallel and not in series.
Let the equivalent resistance be R and let there be 3 resistors namely R1,R2 and R3, connected in a parallel way. Now, the relation is: 1/R = 1/R1 + 1/R2 + 1/R3
In principle, it is infinite. I have not connected a parallel circuit in ages.
I'm assuming that by ' IT ' you mean ' It ' for 'total current'.-- The effective resistance of 2k and 1k in parallel is 2/3 k ohms.-- The power dissipation is I2R = 0.003 x 2/3 k = 2 watts
It is not necessary for anything about them to be the same.All that is necessary is that they create the desired equivalent resistor, having the correct resistance and power dissipation rating without overstressing either resistor.
They are not. They are connected differently, and the voltages and currents behave in different ways.