0
To calculate the mass of 4.87 x 10²⁵ atoms of zinc (Zn), first determine the number of moles of zinc using Avogadro's number (6.022 x 10²³ atoms/mol). Divide the total number of atoms by Avogadro's number: 4.87 x 10²⁵ atoms ÷ 6.022 x 10²³ atoms/mol ≈ 8.09 moles. Then, multiply the number of moles by the molar mass of zinc (approximately 65.38 g/mol) to find the mass: 8.09 moles x 65.38 g/mol ≈ 528.6 grams.
What else can I help you with?
What is the mass of 5.44 x 10 to the 25 power atoms of silver?
By definition, Avogadro's Number, about 6.022 X 1023, for an element is the number of atoms in one gram atomic mass. The gram atomic mass of silver is 107.868. Therefore, the mass of 5.44 X 1025 atoms of silver is [(5.44 X 1025)/(6.022 X 1023)] X 107.868 or 974 grams, to the justified number of significant digits.
What is the mass of 5.49E25 nitrogen atoms?
6.02 x 1023 atoms of nitrogen will weigh 14 g.So, 5.49 x 1025 atoms of nitrogen will weigh 1277 g.
Which subatomic particle has such a small mass that is not used to calculate the atoms atomic mass?
electron
How many moles of He are 1.20 x 1025 atoms?
The element helium does not technically have "moles", because its atomsdo not form any chemical bond with other helium atoms. Its formula unit is a single atom. Avogadro's Number, the number of formula units in a gram atomic mass, is about 6.022 X 1023. Therefore, 1.20 x 1025 atoms constitutes (1.20 X 1025)/(6.022 X 1023) or about 19.9 formula masses, to the justified number of significant digits.
How many moles in 25 g of carbon?
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 25 mole of CO2 has 25 moles of carbon atoms and 50 moles of oxygen atoms.
What is the mass of 5.44 x 10 to the 25 power atoms of silver?
By definition, Avogadro's Number, about 6.022 X 1023, for an element is the number of atoms in one gram atomic mass. The gram atomic mass of silver is 107.868. Therefore, the mass of 5.44 X 1025 atoms of silver is [(5.44 X 1025)/(6.022 X 1023)] X 107.868 or 974 grams, to the justified number of significant digits.
What is the mass of 5.49E25 nitrogen atoms?
6.02 x 1023 atoms of nitrogen will weigh 14 g.So, 5.49 x 1025 atoms of nitrogen will weigh 1277 g.
How many atoms in 1000 g of carbon?
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.1000 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 5.02 × 1025 atoms
Which subatomic particle has such a small mass that is not used to calculate the atoms atomic mass?
electron
How many moles of He are 1.20 x 1025 atoms?
The element helium does not technically have "moles", because its atomsdo not form any chemical bond with other helium atoms. Its formula unit is a single atom. Avogadro's Number, the number of formula units in a gram atomic mass, is about 6.022 X 1023. Therefore, 1.20 x 1025 atoms constitutes (1.20 X 1025)/(6.022 X 1023) or about 19.9 formula masses, to the justified number of significant digits.
What is the mass of Urans?
The mass of Uranus is 8.68 x 1025 kg.
How many grams of silicon would there be in a sample that contained 9.99 x 1025 atoms?
To determine the grams of silicon in the sample, you need to know the molar mass of silicon. Since silicon's atomic mass is approximately 28 g/mol, you can calculate the grams of silicon by dividing the number of atoms by Avogadro's number and then multiplying by silicon's molar mass. This calculation would provide you with the amount of silicon in grams in the given sample.
How many moles in 25 g of carbon?
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 25 mole of CO2 has 25 moles of carbon atoms and 50 moles of oxygen atoms.
How many atoms does 0.5 kg sodium contain?
First calculate the moles of sodium moles = 500 g/ 23 = 21.739 ... Remember the Avogadro Number. 6.022 x 10^(23) is the number of atoms in one mole Hence , multiplying 6.022 x 10^(23) X 21.739... = 1.309 x 10^(25) atoms in 0.5 kg of sodium .
Calculate the mass in grams of 1.2044 and Atilde and 151 1024 atoms of lead (Pb).?
To calculate the mass of 1.2044 × 10²⁴ atoms of lead (Pb), first determine the number of moles using Avogadro's number (approximately 6.022 × 10²³ atoms/mol). The number of moles is calculated as ( \frac{1.2044 \times 10^{24}}{6.022 \times 10^{23}} \approx 2.00 ) moles. The molar mass of lead is about 207.2 g/mol, so the mass is ( 2.00 , \text{moles} \times 207.2 , \text{g/mol} \approx 414.4 , \text{grams} ).
How many atoms are present in 179.0g if iridium?
To find the number of atoms in 179.0 g of iridium (Ir), first determine its molar mass, which is approximately 192.22 g/mol. Next, calculate the number of moles in 179.0 g by dividing the mass by the molar mass: 179.0 g / 192.22 g/mol ≈ 0.933 moles. Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find the total number of atoms: (0.933 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 5.61 \times 10^{23}) atoms.
How many atoms in 5.18 g P?
To find the number of atoms in 5.18 grams of phosphorus (P), first determine the molar mass of phosphorus, which is approximately 30.97 g/mol. Then, calculate the number of moles in 5.18 g by dividing the mass by the molar mass: 5.18 g / 30.97 g/mol ≈ 0.167 moles. Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find the number of atoms: 0.167 moles × (6.022 \times 10^{23}) atoms/mol ≈ (1.01 \times 10^{23}) atoms.
