For this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.
1000 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 5.02 × 1025 atoms
There are approximately 163,163 atoms of carbon in 0.020 g of carbon.
0,515 g of carbon is equal to 0,043 moles.
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C)7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms
1 mole of carbon (or 12 g) has 6 x 1023 atoms. So, 3 moles of carbon (or 36 g) has 18 x 1023 atoms
divide by the atomic mass and times it by advogadro's number.
There are 1 mole of carbon atoms in 12g of carbon. This is because the molar mass of carbon is 12 g/mol, so 12g of carbon is equivalent to 1 mole of carbon atoms.
There are 6.022 x 10^23 atoms in 1 mole of carbon. The molar mass of carbon is 12 g/mol. Therefore, in 72.0 g of carbon, there are (72.0 g / 12 g/mol) * 6.022 x 10^23 atoms = 3.61 x 10^24 atoms of carbon.
There are approximately 2.42 x 10^22 atoms in 1 cm^3 of carbon, assuming a density of 2.26 g/cm^3 and an atomic weight of 12.011 g/mol for carbon.
To find the number of carbon atoms in 12 g of carbon (C), you first need to calculate the number of moles of carbon (C) in 12 g using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23) to determine the number of atoms in that many moles of carbon (C).
There are approximately 1.34 x 10^22 carbon atoms in 1.6 g of carbon. This calculation is based on the molar mass of carbon (12 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol). To find the number of atoms, divide the mass of the sample by the molar mass of carbon, and then multiply by Avogadro's number.
To calculate the number of atoms in 63.5 g of carbon monoxide, first determine the number of moles of carbon monoxide using its molar mass (28.01 g/mol). Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms. A single molecule of carbon monoxide consists of 1 carbon atom and 1 oxygen atom.
To find the number of carbon atoms in 77.28 g of ethane (C2H6), first calculate the molar mass of ethane, which is approximately 30.07 g/mol. Next, divide the mass of ethane by its molar mass: 77.28 g / 30.07 g/mol ≈ 2.57 moles of ethane. Since each molecule of ethane contains 2 carbon atoms, multiply the number of moles by 2: 2.57 moles × 2 = 5.14 moles of carbon atoms. Finally, convert moles of carbon to atoms using Avogadro's number (approximately 6.022 x 10²³ atoms/mol): 5.14 moles × 6.022 x 10²³ atoms/mol ≈ 3.09 x 10²⁴ carbon atoms.