1.6 g C x 1 mol C/12 g x 6.02x10^23 atoms/mol = 8.1x10^22 atoms
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C)7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms
Since 12 g C is 1.0 mole C there are 6.02*10+23 atoms in (each) mole; that's the definition of a mole
16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S
The number of atoms of lead is 6,68.10e23.
1 mole of NaHCO3 Na = 1 * 22.99 g = 22.99 g H = 1 * 1.01 g = 1.01 g C = 1 * 12.01 g = 12.01 g O = 3 * 16.00 g = 48.00 g Total = 84.01 g There are 84.01 grams in one mole of NaHCO3.
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C)7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms
169 g C x 1 mole C/12.011 g x 6.02x10^23 atoms/mole = 8.47x10^24 atoms
The number of atoms is 28,099.10e23.
Since 12 g C is 1.0 mole C there are 6.02*10+23 atoms in (each) mole; that's the definition of a mole
Carbohydrates do not contain "g" atoms. Thus we can not answer your question.
16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S
One mole of any element contains 6.02 x 1023 atoms. So 1mole of carbon = 6.02x1023 atoms. 0.8mole of carbon = 0.8 x 6.02x1023 0.8 mole of carbon = 4.816 x 1023
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
The number of atoms of lead is 6,68.10e23.
divide by the atomic mass and times it by advogadro's number.
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
1 mole of NaHCO3 Na = 1 * 22.99 g = 22.99 g H = 1 * 1.01 g = 1.01 g C = 1 * 12.01 g = 12.01 g O = 3 * 16.00 g = 48.00 g Total = 84.01 g There are 84.01 grams in one mole of NaHCO3.