0.75 mole of carbon atoms (6.022 X 1023 /1 mole C x 0.75) = 4.52 X 1023 carbon atoms
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
A non cyclic alkane always has a number of hydrogen atoms equal to 2c + 2, where c is the number of carbon atoms. Therefore, hexadecane, an alkane with 16 carbon atoms, will have 34 hydrogen atoms.
One mole of any element contains 6.02 x 1023 atoms. So 1mole of carbon = 6.02x1023 atoms. 0.8mole of carbon = 0.8 x 6.02x1023 0.8 mole of carbon = 4.816 x 1023
There are 3 Carbon atoms in C3H4. The numbers following the Element names (Like C, or H, or Na) is the amount of atoms in the compound. So there are 3 Carbon atoms and 4 Hydrogen atoms. That is incorrect the answer would be 4.53 x 1023 carbon molecules
1 mole C = 12.011g C = 6.022 x 1023 atoms C 0.020g C x (6.022 x 1023 atoms C)/12.011g C = 1.0 x 1021 atoms C
Carbon-13 make up 1.1% of carbon atoms. .011 x 19000 carbon atoms = 209 carbon-13 atoms present.
0.75 mole of carbon atoms (6.022 X 1023 /1 mole C x 0.75) = 4.52 X 1023 carbon atoms
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C)7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms
Three: 1 C and 2 O atoms
These are compound out of many Carbon and Hydrogen atom,In a single bonded and non cyclic carbon chain with as much as possible (= 'saturated with') single bonded H atoms to the C atoms.
31.8 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C)= 1.59 X 1024 atoms of carbon===================
17 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 8.5 X 1023 atoms of carbon =====================
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
One Carbon (C) atom and two Oxygen atoms (O). CO2.
A non cyclic alkane always has a number of hydrogen atoms equal to 2c + 2, where c is the number of carbon atoms. Therefore, hexadecane, an alkane with 16 carbon atoms, will have 34 hydrogen atoms.
There are three carbon atoms and three oxygen atoms in each pyruvate molecule.