Can use this way.
-log(0.001) = 3
14 - 3
= a pH of 11.0
Wiki User
∙ 13y agoTo calculate the pH of a 0.001 M NaOH solution, you can use the formula pH = 14 - pOH. Since NaOH is a strong base that completely dissociates in water, the pOH can be directly calculated as -log(0.001) = 3. Thus, the pH of the solution would be 14 - 3 = 11.
Nicholas Raether
9
The pH of a 0.001N NaOH solution is around 11.9. NaOH is a strong base, and at this concentration, it will result in a highly alkaline solution.
To calculate the amount of NaOH needed to increase the pH from 8 to 10, you need to consider the volume of the solution and the concentration of NaOH. Using the equation pH = -log[H+], you can determine the concentration of H+ ions at pH 8 and pH 10, then calculate the amount of NaOH needed to neutralize the difference in H+ ions to reach pH 10.
To calculate the pH of the resulting solution when mixing HCl and NaOH, you need to determine the moles of each reactant. Use these values to find the limiting reagent and the excess reagent. Then, calculate the concentration of the excess reagent left in solution. Finally, use the concentrations of the excess reagent and water to determine the pH of the resulting solution.
To calculate the pH of the solution after mixing, first find the moles of acetic acid (HOAc) and NaOH. Then, determine which reactant is limiting to find the excess OH-. Use the excess OH- to calculate the concentration of OH- in the final solution, and then use this to calculate the pH.
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
To calculate the pH after each volume of NaOH is added, you need to determine the moles of HBr initially, moles of NaOH added, and then use these values to calculate the final concentration of H3O+ ions in the solution. From there, you can calculate the pH using the equation pH = -log[H3O+]. Repeat these calculations for each volume of NaOH added to find the pH at 12.5 ml, 18.7 ml, 20.0 ml, 29.5 ml, and 34.2 ml.
To calculate the amount of NaOH needed to increase the pH from 8 to 10, you need to consider the volume of the solution and the concentration of NaOH. Using the equation pH = -log[H+], you can determine the concentration of H+ ions at pH 8 and pH 10, then calculate the amount of NaOH needed to neutralize the difference in H+ ions to reach pH 10.
To calculate the pH of the resulting solution when mixing HCl and NaOH, you need to determine the moles of each reactant. Use these values to find the limiting reagent and the excess reagent. Then, calculate the concentration of the excess reagent left in solution. Finally, use the concentrations of the excess reagent and water to determine the pH of the resulting solution.
The pH of a 0.001N NaOH solution is around 11.9. NaOH is a strong base, and at this concentration, it will result in a highly alkaline solution.
To calculate the pH of the solution after mixing, first find the moles of acetic acid (HOAc) and NaOH. Then, determine which reactant is limiting to find the excess OH-. Use the excess OH- to calculate the concentration of OH- in the final solution, and then use this to calculate the pH.
To find the pH of the solution, first calculate the moles of OH- from each solution (Ca(OH)2 and NaOH). Then, add the moles of OH- together and calculate the total volume of the combined solutions. Finally, use the concentration of OH- ions in the combined solution to calculate the pOH and pH of the solution.
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
The pH of a 0.002M solution of NaOH is around 11.98. This is because NaOH is a strong base that dissociates completely in water to produce hydroxide ions, which lead to the alkaline pH.
To determine the pH of the solution formed when NaOH and HCl react, first calculate the moles of NaOH and HCl used in the reaction. Then identify the limiting reactant, which in this case is the one that is completely consumed first. Use the moles of the limiting reactant to determine the concentration of the remaining reactant in the solution. Finally, use this concentration to calculate the concentration of OH- or H+ ions in the solution and then convert it to pH using the formula pH = -log[H+].
How to work it out - Calculate the concentration of the solution in terms of molarity. Calculate the hydrogen ion concentration from the fact that multiplying the hydrogen and hydroxide concentrations (in mols per litre) will always give 1x10-14. Take the -log10 of the hydrogen ion concentration.
The pH of a 10^-4 M NaOH solution is around 10. This is because sodium hydroxide is a strong base that dissociates in water to produce hydroxide ions, which increase the pH of the solution.
The pH of a 1.0 x 10^-6 M NaOH solution is approximately 11.00. This is because NaOH is a strong base that dissociates completely in solution to produce hydroxide ions, resulting in a high pH.