To find the length of the string we use length method. The length property returns the length of a string (number of characters we use).The length of an empty string is 0.
For example:
function myFunction() {
var str = "Hello World!";
var n = str.length;
Hope this hepls.
Well, the length of any string in java can be measured as follows.
String s = "Example";
int len = s.length(); //the length() method calculates total no of chars in string s
System.out.println( "Length of the above string is " + len );
int countString(String word,String orginalString){
String delimiters = "+-*/(),. ";
StringTokenizer st = new StringTokenizer(orginalString, delimiters, true);
int count=0;
while (st.hasMoreTokens()) {
String w = st.nextToken();
if (w.equals(word)) {
result = ++;
}
return result;
}
}
This method returns the length of a string. The length is equal to the number of 16-bit Unicode characters in a strong. Syntax: public int length(). There is a Java input which can be used in order to determine the length of a string.
// Number of characters in String str:
str.toCharArray().length;
// or, more directly:
str.length();
CODE:
String a = "hello";
System.out.println(a.length());
OUTPUT:
5
In Delphi Pascal, it is:
var
s: string;
x: integer;
begin
s:='How many characters is this?';
x:=Length(s);
end;
declaration of number of characters in string[] e.g.
string[12];
string[21];
string[5];
declares 12,21, and 5 characters respectively
Use the strlen() function in the C standard library.
length() method in a String returns the number of characters in that String.
String s = "abc";
System.out.println(s.length()); // this outputs "3"
Use the following function to count the number of digits in a string. size_t count_digits (const std::string& str) { size_t count = 0; for (std::string::const_iterator it=str.begin(); it!=str.end(); ++it) { const char& c = *it; if (c>='0' && c<='9'); ++count; } return count; }
public int getStringLength(String val) { return val.length(); } There is an inbuilt functionality in strings that counts the number of alphabets in a string called length()
Console.WriteLine("Please input a string:"); string str = Console.ReadLine(); Console.WriteLine("Number of characters: " + str.Length);
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
class Count { public static void main(String args[]) { int i,c=0; int n=args.length; System.out.println("length is"+n); for(i=0;i<args.length;i++) { System.out.println(args[i]); c++; } System.out.println("number of words="+c); } }
use Microsoft word
Use the following function to count the number of digits in a string. size_t count_digits (const std::string& str) { size_t count = 0; for (std::string::const_iterator it=str.begin(); it!=str.end(); ++it) { const char& c = *it; if (c>='0' && c<='9'); ++count; } return count; }
Assuming you want to count the number of characters in a String, you just need to call the length() method on the object. For example: String foo = "This is a string"; System.out.println(foo.length()); The above code would result in the number 16 being printed out.
public int getStringLength(String val) { return val.length(); } There is an inbuilt functionality in strings that counts the number of alphabets in a string called length()
Console.WriteLine("Please input a string:"); string str = Console.ReadLine(); Console.WriteLine("Number of characters: " + str.Length);
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
class Count { public static void main(String args[]) { int i,c=0; int n=args.length; System.out.println("length is"+n); for(i=0;i<args.length;i++) { System.out.println(args[i]); c++; } System.out.println("number of words="+c); } }
public class count { public static void main(String[] args) { String string = "1 2 3 4"; char[] array = string.toCharArray(); System.out.println("Number of characters in string: " + string.length()); System.out.println("Number of characters in array: " + array.length); } } Output: Number of characters in string: 7 Number of characters in array: 7 So yes, spaces are taken as single characters in a string.
#include<iostream> #include<string> using namespace std; int main() { int count=0; string b; string a[6]={"technical","school","technical","hawler","school","technical"}; for(int i=0;i<6;i++) { b=a[i]; for(int j=i;j<6;j++) { if(a[j]==b) count++; } cout<<a[i]<<" "<<count<<endl; count=0; } return 0; }
substr(string, position [, count]) It extract substring starting from start and going for count characters. If count is not specified, the string is clipped from the start till the end
Word Count
you can count them all one by one or usally you can find it on the internet.