From the 16 bits reserved for the host, you "lend" 3 bits for the subnet. That gives you the possibility of dividing into eight subnets. The remaining 13 bits indicate the host in each subnet. - To see the complete steps in more detail, do some internet searching on subnetting.
The classful network A provides 16,777,216, the most available in classful networks.Unfortunately a class A network only allows for 256 possible networks.This is of course IPv4 stuffRemember the entire IPv4 address space is 32 bits wideIn class A the network mask is 255.0.0.0 meaning that the first octet or eight spaces are reserved for networks and the remaining 24 bits are available for host.OK so the number of host are 2^24 or 16,777,216 English 16 million 777 thousand and 216 hostsAnd don't forget all networks and subnets require reserving the first and last address for the network and the broadcast address.
It is an eight hour class
1 third divide 6 eight = 0.16666666666666666
The quotient is 6
75
8/0 = 0 you can't divide by zero
If you divide eight by pi, you get 2.54647909 as the diameter. If you divide eight by 3.14 (simplified pi), you get 2.54777070 as the diameter.
yes
0.2353
You cannot divide by 0.
67.6
eight pounds.