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To increase voltage output when using more then one battery connect the batteries in series.
battery produces voltage by
Series.
The batteries can be connected in parallel or in series. In parallel, good batteries of the same voltage will have a total voltage across them equal to the voltage across one of them. Those batteries in series will have a total voltage equal to the sum of the voltage of each of the batteries.
If the 2nd battery is connected "in series" with the 1st battery, the voltage will increase & the motor will run faster. If the 2nd battery is connected "in parallel" with the 1st battery, the voltage will not change, but the total battery capacity will be greater & therefore battery life will be longer than when using just 1 battery.
Because the original voltage of the battery weakens over time after using it for awhile making the voltage less then the original amount stated on the battery.
we can use a dc voltage directly from a dc source with parameters equal that of the battery
use a metals further away from each other on the reactivity series (I think). but using more electrolytes (more fruits i.e. 4 lemons instead of 1 etc) will definitely give a higher voltage. the more fruit, the bigger the voltage. :D
If it is a 1.5 volt bulb you can connect it through a series circuit directly to your battery. If the bulb is not made to run on 1.5 volts and needs another voltage, it may not light up!
Batteries are storing charge or free electrons. The state is by nature a fixed voltage rather than a varying voltage. You can convert the battery charge to AC by using what is called an inverter.
Voltage can be calculated using Ohm's Law:Voltage = Current (A) x Resistance (Ω)Voltage = 4A x 3Ω = 12 VoltsTherefore, the battery is a 12 Volts.The power dissipated is Voltage x CurrentPower = 4A x 12V = 48 Watts
You can test a battery by using multimeter. Set the multimeter to the DC voltmeter setting and then place the leads of the multimeter across the leads of the battery. the multimeter will have a readout of the voltage.