You question does not say what size DC motor you are wanting to control, so this answer will have to be generic.
First of all, you DON'T drop the voltage "OF" the DC motor, you drop the voltage "TO" the motor.
The simple answer is to place a "RESISTANCE," or "RESISTOR" in series with the motor. A resistor limits the amount of current flowing through it, and thus the voltage.
If you are talking about the very small DC hobby type motors [designed for 1 to 3 volt inputs], one way would be to use a variable resistor, like a large potentiometer ["pot"], scavanged out of a discarded "old" TV or "old" radio [both "pre" solid state era].
Another trick I've used [requires a lot of trial and error] is to use an assortment of old [but working] incandescent/filiment type light bulbs [small, like from flashlights, Christmas tree bulbs, dial lights from "old" radios and TVs, etc.] as resistors.
You can experiment around with "stacking" these in series to add more resistance, with each addition slowing the motor more. And if even the largest of them slows the motor TOO MUCH, then they can be wired in PARALLEL to decrease resistance, allowing more current flow. As said above, this can require much trial and error, but it can be made to work.
Another method [if using batteries] would be to use fewer batteries in series. This only works for larger voltage motors, like out of 24/18/12/9/7.2 volt motors [like out of cordless drills for example].
As an example, consider using an 18 volt motor. To provide the "normal" 18 volts would require 12 1.5 volt alkaline batteries in series. If you used only 6 batteries, you would have reduced the voltage by half. By varying the number of batteries, you would be able to vary the motor speed. Remember however, that there is a limit to how much you can "starve" the motor and still have it run or do any work.
If your aplication allows you to use an AC power source, then another method [much more expensive] would be to use a benchtop AC powered, variable power supply.
AnswerAnother common method is pulse width modulation (PWM). The full available voltage is switched on and short time later it is turned off again. This cycle repeats continuously at a relatively high frequency (hundreds, to tens of thousands of times per second). The ratio of the on-time to the off-time determines the apparent percentage of the DC supply that the motor sees.
The circuits to drive motors this way can be relatively simple to extremely complex, depending on the size of the motor, available DC voltage, and other controls needed (such as controlling speed instead of voltage supplied to the motor).
ANSWER: motor are not voltage related but rather power related so the answer is not to reduce the voltage but to reduce the power going to it. REDUCE THE POWER WILL REDUCE THE SPEED. either reducing current and /or voltage will do the trick.
u can simply use a variable resistor to decrease the speed of motor. as resistor limits the amount of current flow in the load , thereby decreasing the amount of current . u can adjust the speed as per your need
As you asked the question and it was added it to the electrical category I am presuming that you are talking about electrical generation. The prime mover has to be kept at a constant speed. The speed of the prime mover governs the frequency of the voltage generated. As the load increases the engine will start to slow down. The engine's speed governor senses this drop in RPM, hence the drop in frequency, and increases the fuel supply to the engine by advancing the diesel engine's fuel rack. This action increases the engine speed and brings the generated frequency back to the required system frequency.Also as the load increases, the output voltage will start to decrease. The output voltage is controlled by the generator's voltage regulator. When the decrease in voltage is sensed by the voltage regulator, it increases the generator's field excitation voltage which will bring the voltage back to the required system voltage.These actions are going on continuously, balancing each other all the time the engine is running and the generator is producing an output voltage.
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When the temperature of molten rock begins to drop there is a loss of energy thatcauses ions to slow down. As the ions slow down, they group together and arrange themselves into orderly crystalline structures. This process is referred to as crystallization.As crystallization continues, these individual silicon-oxygen tetrahedrons joinwith one another, and other ions, to form the basic structure of most minerals andigneous rocks.
the country will be shrinking at a slow rate birth rates will drop slightly
Chemical reactions slow down in the cold. The electricity produced in a car battery is the result of chemical reactions between the sulfuric acid and the lead plates. Slow down those reactions and the battery is not able to produce its normal current.
Install a rheostat in series with the motor.
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Depends on what sort of motor it was. If it was the sort you find in an ordinary electric drill, then it would slow down. But rememer, the only way you can reasonably reduce the current in to motor is to reduce the voltage in the supply. A motor takes what current it can, dependent on Ohm's Law. To reduce the current, reduce the voltage. But in a three-phase motor, the speed being dependent on the rotation of the phases, it would more or less stay the same. But this assumes it's not under load. A load would cause it to slow down.
Assuming the sine wave's angular frequency is what's changing, the motor will speed up and slow down in proportion to that frequency.
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The blower motor is tired. It will eventually blow a fuse and/or burn out the blower motor speed resistor. Time to replace the blower motor. Also check connections for high resistance damage (melted connections).
No, electricity will not slow down with increased resistance. The number of electrons moving through a conductor will decrease with increased resistance. Also there will be a drop in the voltage (electrical pressure) with increased resistance. Look up Ohms Law for formulas relating to voltage, resistance, and amplitude. E=I*R. E=voltage (pressure), I=the current (flow of electrons) R=the amount of resistance or the strength of the opposing flow of electrons. The speed of an electron through a conduvtor will always remain the same.
With increasing torque load the armature tends to slow down; the motor draws more current to compensate, and if there is armature resistance the back emf generated by the armature falls to allow the increased current to flow, which causes the motor to settle at a lower speed. The mechanical output power is the speed times the torque, and increasing the torque increases the power output provided the speed does not drop much.
its when something is slowing down
Replace the slow headlight motor.
A generator's terminal voltage can be raised by increasing the field current. This will result in an increased load on the generator, which will slow it down unless the governor kicks in to keep the generator at speed.