you should figure it out yourslf dumb a$$
A transformer is used before rectification, and is to change the voltage to a suitable figure (usually a lower one than he mains supply).
don't overload it, have a look on the transformer their should be an input voltage and an output voltage if take fails just try and see if u can overload it when you do try and figure out the voltage and get a new transformer;)!!!!!
The secondary current is determined by the load, not by the transformer. But the load current mustn't continuously exceed the rated current of the secondary winding. To determine the secondary rated current, you need to know the rated secondary voltage of the transformer, and divide 315 kV.A by this figure.Incidentally, the correct symbol for 'kilovolt ampere' is 'kV.A', not 'kva'.
If you know the voltage and resistance, then current = voltage divided by resistance. Otherwise, you can attach an ammeter into the circuit (in series).
If you are referring to voltage drops in a series a.c. circuit, then you simply multiply the current through each impedance by the value of the individual impedances.
If you have the Maximum clock frequency, then you can figure out the minimum clock period using this formula: 1/(minimum clock period) = (Maximum clock frequency).
If total voltage and current are known then, Rt = Vt/It will figure total resistance.If total power and total voltage are known then Rt = Vt2/Pt will figure total resistance.If total power and total current are known then Rt = Pt/It2 will figure total resistance.If the total current or voltage and power of all the components in the circuit are known then add all the power values to get Pt, and then you can use either Rt = Vt2/Pt or Rt = Pt/It2 to figure total resistance.
External voltage is the ration when there is an increase in current and voltage. If you apply voltage to the outside of a circuit and need to figure out the amount of current flow, that would be the external resistance.
An indispensable first step would have to be to find a clear definition of what is meant by a "parallel series circuit", as no such configuration is taken up in standard engineering texts.
The outout current will be less / much smaller than input current.
Figure of merit = 1/ Current Sensitivity.
Ohm's Law relates Voltage, Current, and Resistance. The equation is Voltage = Current times Resistance. Knowing any two, you can figure out the third, and that is one of the principles of basic circuit analysis.
In an AC circuit the voltage and current are n the form of a sine wave that goes between a maximum and minimum value 60 times a second. Measuring the difference between these values is a peak-to-peak measurement. Root Mean Square (RMS) computes an average (mean). To convert RMS to peak, multiply the RMS figure by 1.41. 1.41 is an approximation of the value of the square root of 2.
please show me how to figure it out.
Add up the bulbs and you will have the total wattage for that circuit. Let's say it is a typical 120Vac household circuit. 15 amps is the maximum that circuit will handle. Current (amps) is calculated by: I = Power (wattage) / Volts, so for example: I = (10) 100 watt light bulbs / 120 Current = 1000/120 = 8.3 amps, You are safe, In reverse, to figure out how many bulbs you can have: Multiply the bulb wattage by the number of bulbs you have (on an individual crkt). This cannot exceed 1800. 1800 is the total wattage allowed for a 15 amp, 120V circuit. The same is true for any device used on a circuit. Toaster, radio, etc. The wattages will be listed on the device. Is your circuit a temporary "work site" type bulb stringer?
A voltage drop is the difference in potential between opposite ends of an electrical component when current is flowing through that component. In a d.c. circuit, this is the product of the component's resistance and the value of the current passing through it.
in max a maximum ride novel
Figure it out yourself.
Oil or similar is used as a cooling fluid in electrical transformer, because it is electrically insulating - which water is not. The figure of merit is the lack of conductivity.
What is the budget figure of Pakistan in 2009?
For a d.c. circuit, you divide its supply voltage by the resistance of its load. For an a.c. circuit, you divide its supply voltage by the impedance of its load.
Noise figure is one of those cases that is crucial, and that calls for experienced care about
The equation that you are looking for is W = I x E. Watts = Amps x Volts.. As you can see if no voltage is given the question can not be answered. Once you supply the voltage and multiply it by the maximum amperage you stated, the results will be maximum wattage. Divide this figure by 8.5 and you will find the maximum number of lamps that you can add to this circuit.