External voltage is the ration when there is an increase in current and voltage. If you apply voltage to the outside of a circuit and need to figure out the amount of current flow, that would be the external resistance.
it is the resistance with which the generatoe just excite.
Short answer: yes. Most modern multimeters will not be damaged by external power when measuring resistance. But they will give erroneous readings. It is best to remove the power and disconnect the measured resistance from the larger circuit. A multimeter determines resistance by applying a small voltage, and measuring the resulting current. If the resistor has an external voltage source, then it will interfere with the measurement. Furthermore, if the resistance is connected to a larger circuit, then the resistance of this larger circuit will also be involved.
if the diode is forward biasedwell practically the current flows in a circuit if and only if an effective resistance is present in the circuit, if we consider the diode to be ideal (barrier potential but no internal resistance) in this case an external resistance is required if we use the approximate model (both barrier potential and internal resistance are considered) we need not use an external resistance the internal resistance itself acts as the effective resistance.if the diode is reverse biased:-the same explanation applies even if the diode is reverse biased but one must take care that the reverse voltage drop on diode should not increase the peak inverse voltage mark the diode would be burnt or damaged if this phenomena occurs.So this can be prevented by adding suitable resistance to the circuit through which the voltage drop on diode can be managed
in case of ideal voltage source we consider the internal resistance to be zero.but in practical,every battery has some internal resistance then if you connect a load resistance across the terminals of that source,the net potential difference's across the voltage source will be a function of external resistance connects it won't give constant voltage across it's terminals.
extra resistance is added in order to decrease starting current and improve starting torque
it is the resistance with which the generatoe just excite.
gravity air resistance water resistance friction
As the source impedance is equal to load impedance, it is assumed that both the resistances are in series. This distributes the whole voltage equally between both the impedance. Hence the PD across external resistance will be 1V.
Gravity air resistance water resistance friction
If Rin = Rout, then the voltage at the output of the device goes down to half of the value that the circuit has without the external resistance. Scroll down to related links and look at "Interconnection of two audio units".
An electron traveling through the wires and loads of the external circuit encounters resistance.
R=1/(1/ R1 +1/ R2 +1/ R3 +.........) Where R is the total external resistance(effective resistance) in an electric circuit.
R=1/(1/ R1 +1/ R2 +1/ R3 +.........) Where R is the total external resistance(effective resistance) in an electric circuit.
Ohms are the unit of measurement for resistance, so an ohmmeter is a device that measures electrical resistance. A galvanometer measures the current flowing through the resistance, so the two are related. To convert a galvanometer into an ohmmeter, one needs an external battery.
Short answer: yes. Most modern multimeters will not be damaged by external power when measuring resistance. But they will give erroneous readings. It is best to remove the power and disconnect the measured resistance from the larger circuit. A multimeter determines resistance by applying a small voltage, and measuring the resulting current. If the resistor has an external voltage source, then it will interfere with the measurement. Furthermore, if the resistance is connected to a larger circuit, then the resistance of this larger circuit will also be involved.
unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance
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