if the diode is forward biased
well practically the current flows in a circuit if and only if an effective resistance is present in the circuit, if we consider the diode to be ideal (barrier potential but no internal resistance) in this case an external resistance is required if we use the approximate model (both barrier potential and internal resistance are considered) we need not use an external resistance the internal resistance itself acts as the effective resistance.
if the diode is reverse biased:-
the same explanation applies even if the diode is reverse biased but one must take care that the reverse voltage drop on diode should not increase the peak inverse voltage mark the diode would be burnt or damaged if this phenomena occurs.So this can be prevented by adding suitable resistance to the circuit through which the voltage drop on diode can be managed
If diode is connected in series then current will flow only in one direction. ie. Current flow occurs only when diode is forward biased. ANSWER: It depends are the diodes are connected in series if they are back to back no current will flow if connected in the forward conduction mode then they will conduct.
If they are in series, you need to add the resistance values.
Series circuit: The total voltage is the sum of the voltage on each component. The total resistance is equal to the sum of the resistance on each component. The total current is equal in every component.
Yes. this is commonly done. However, performance is better and costs lower if you use the proper diode for production devices. Absolutely NOT. For the same reason that capacitor cannot be added in series to withstand higher voltage. Not all components are made equally Supposed that you have two diodes rated at 100v add them in series makes 200v not quite if one leaks more then the other unequal voltage will results blowing them up. There is a simple solution add a parallel high resistor across each component to equalize the voltage then YES it is possible to add them in series
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
If diode is connected in series then current will flow only in one direction. ie. Current flow occurs only when diode is forward biased. ANSWER: It depends are the diodes are connected in series if they are back to back no current will flow if connected in the forward conduction mode then they will conduct.
Add all the individual resistance values.
If you add a second resistor, the resistance of series circuit will increase.
For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.
You raise the total resistance by that amount if added in series to a circuit. If you add them in parallel to a circuit then that total resistance will be less than the total of the added circuit.
If they are in series, you need to add the resistance values.
Since resistance is the ratio of voltage to current, if the voltage is constant then increasing the resistance will result in a reduction in current.
i think first one should find out the series resistance that is R1+R2+R3 and after that parellel resistance that is 1/R1+1/R2+1/R3 and after that add the series resistance and parellel resistance to get the total resistance
RSeries = SummationI=1toN (RI) Simple answer; add them up.
Add the two together. For instance, two 100 ohm resistors in series have a total resistance of 200 ohms.
its the same as normal resistance, so if you wanted to add the resistors when in parallel you would add them by 1/R1 +1/R2=. If they were in series you would simply add.
When resistors are wired in series, their resistances are added to find the total resistance. If they are run in parallel, or series-parallel, the formula is different