Hello, Velocity in a pipe is the flow divided by the area. If the pipe is full, the area is simply pi*r². Here is a useful calulator for full pipes: http://www.tasonline.co.za/toolbox/pipe/velocity.htm
velocity = quantity of water flow/area of the pipe( v = q/a)
It's lacking the temperature of water to calculate its velocity having the pressure and the diameter of the pipe. The temperature of water also counts on this equation. The equation is valid for fresh water, if the density of the water is higher compared to the fresh water, the result will vary, too. It is lacking also the inner condition of the pipe. Smooth or rough. The pipe must be placed horizontally, 0º degree of inclination. The pipe must be fully straight, too.
Yes, it is actually one of the questions on a master plumbers exam
Depends on the internal diameter, and the flow velocity. Velocity of water = Delta V Internal Radius= R RxRxV= Volume
to find the velocity of water in a pipe use the equation Q = VA where Q = the total volume of water running through the pipe in cubic feet per second V = the velocity of the water A = the cross sectional area of the pipe. (remember area = r^2*pi or D^2/4*pi). If you have the radius in inches find the area in inches and divide by 144 (1 square foot) this will yield the area in ft^2. you need to know how much water is running through the pipe (Q) - say 5 cfs and the area of the pipe (A) - say 1 ft^2 rearrange the previous equation V = Q/A and you get V = 5cfs/ 1 ft^2 = 5 fps
Static pressure is .434 X height Example 10 ft x .434 4.34 PSI to prove take 2.31 PSI x 4.34 To find FORCE to need to calculate the diameter of the piping and the height and then the weight of the water inside the pipe
2460 m/s
Maximum allowable water velocity is generally kept as 3m/sec. But we have seen higher velocities also work.
The Head just before entry to the pipe becomes velocity Head at the exit of the pipe. Assuming no losses: H=u^2/2g --> u=Square root of (2gH) where H is the height of the height of the level of water in the tank above the outlet of the pipe and u is the velocity. The velocity is such that if the water left the pipe vertically upwards and assuming no losses of any sort, the water would stop at the same level as the water in the tank. The volume flow rate is then uA where A is the area of the pipe, ie (πd^2)/4 Make sure you use the same units eg, u in meters per second, d and H in meters, g=9.81 m/s^2
flow is proportional to velocity so its dependent on how fast the waters moving and the size of the pipe... check out the hazen williams nomograph
I think velocity is directly proportionate to its applying pressure.
The velocity is constant in a steady flow pipe while in the unsteady flow the velocity is not constant.
the velocity of water flow within a drainage pipe; the equation is V=L/t L= Length t=time. Then the flow rate; Fr=A*V, Where A= sectional area and V = velocity.