Using Snell's law, n(1)=(n(2) x sin angle (2)) / sin angle (1).
n(1)= The refractive index of the more optically dense medium.
n(2)= The refractive index of the less optically dense medium.
angle (1)= The critical angle of the two mediums.
angle (2)= 90 degrees since when light is at the critical angle it undergoes total internal reflection.
Since sin 90= 1, this can be ignored, resulting in n(1)= n(2) / sin angle (1)
priciple of finding refractive index of liquid using convex lens
is the two human body have different refractive index
Refractive index=Sin i divided by Sin r where r= angle of refractioni= angle of incidenceLight rays hitting the boundary at an angle of 23° is refracted at 90° to the normal. Therefore, r= 90 and Sin 90° = 1 . This implies that Refractive index= Sin i=Sin21°= 0.36Speed of light in liquid= Speed of light in air divided by refractive index= 300000000 Divided by 0.36= 833333333.3 m/s
What is carvedilol phosphate Refractive index in Hexane
Refractive Index of water=1.333 Refractive Index of Sea water=1.343
The refractive index is 1,46-1,46 at at 20 oC.
Usually a convex lens made up a material with higher refractive index would act as a converging device when kept in a medium having lower refractive index such as air. But when it is kept in a liquid as said with higher refractive index then convex lens would become as a concave lens. Now it would diverge the rays entering through it right from the liquid with higher refractive index.
No pure mirror refracts. Refraction is caused by a change of the medium through which the light passes, which is accompanied by change of refractive index (change in the velocity of the light).
determine the refractive index of a transparent liqiud
When it is immersed into the liquid of refractive index greater than to that of the lens material.
The "nature" of it is the same as if it weren't immersed. However, if it has the same refractive index as the material it's immersed in, it will no longer have any discernable effect on the refraction of light; from the outside it will appear to just be another part of the liquid (it may well disappear from sight, since it's no longer visually distinguishable from the liquid itself).
yes...when the lens is immersed in a liquid whose refractive index is greater than that of the material of the lens, for example, an air bubble inside water....
They are both made of a transparent medium with a refractive index > 1.Both have one or two sides possessing a curvature which, combined with their refractive properties, causes light rays to be deflected(convex ()> ) or (concave )(< )
Refractive Index: 1.4465
Refractive index of vacuum is 1.
Refractive Index: 2.4175-2.4178
"The refractive index of water is 4 / 3" means the refractive index of water with respect to air. "The refractive index of glass is 3 /2" means the refractive index of glass with respect to air. You change the question as ," what is the refractive index of glass with respect to water? The answer is it is the ratio of refractive index of of glass with respect to air to the refractive index of water with respect to air =( 3/2) divided by( 4/3) = 1.125
I assume "molecular refractive index" refers to "the refractive index of a group of molecules". In this case, you just use the units for a refractive index - i.e., a dimensionless number.