If you have one pen that is larger than the rest you can put the extra one in there or you could sell or butcher the extra one.
eat 5 sheep
1, 3 and 9.
60 pens. 60 2 = 30 60 3 = 20 60 4 = 15 60 5 = 12 60 6 = 10 - Chow
The highest common factor is 3
Yes, all these: 1, 2, 3, 4, 6, 12.
3 pens to go shopping
15 pens. 5 pencils.
Put 5 sheep in each of three small pens... THEN - build a larger pen enclosing the three smaller ones. The smaller pens each have an odd number of sheep in them (5 in each) - and the large pen has a total of 15 sheep enclosed within it !
If 8/11 pens are blue, then 3/11 are black. There are 12 black pens, so 12/(3/11) = 44. So there are 44 pens total. 44 * (8/11) tells us that 32 pens are black.
Not evenly. The answer is _.
Yes, but not evenly.
3b + r = 20 20/4=5 5x3=15 blue pens 5x1= 5 red pens