by analyzing your three input logic network
There is no need for a combinatorial circuit to multiply a number by two. A binary number, left shifted one place, is twice the original binary number. The specific answer to the question is that you would connect the three input lines to the three high order output line of four output lines, and connect the low order bit of the four output lines to logic 0. If the three input lines were labelled A, B, and C, the output would be A, B, C, and 0.
If you look at the 7486 IC datasheet you can see, it have 4 independence XOR gates with 2 inputs. So you can only use 2 inputs if you see it like that. But if you understand the truth table of XOR gate you can have 3 input application using 7486 IC. Here I will show you how. 1.Get the first 2 input into the first XOR gate. 2.Then get the 3rd input together with the Output from the first 2 input XOR gate into another gate. 3.This output should be the result of 3 input XOR gate. Check this output with 3 input truth table to confirm the answer.
C++ does not support octal encoding within source code (only decimal and hexadecimal are supported), so the octal must be represented with a string. The binary output must also be a string. Every octal digit represents three bits of binary, thus the binary output string will always be three times the length of the octal input string. The loop will begin with the octal character at index 0 and work through each character from left to right. On each iteration, the binary output string will be appended with a 3-character string, as follows: octal = binary "0" = "000" "1" = "001" "2" = "010" "3" = "011" "4" = "100" "5" = "101" "6" = "110" "7" = "111" Thus octal input "437" will begin with the "4" producing an output of "100". On the next iteration, "3" will append "011" to produce "100011". On the final iteration, "7" will append "111" to produce "100011111".
If you know that the number input will always be three digits: output = 10 * (int)(input / 100) + (input % 10); If you want to idiot proof it (eg. too many digits): output = 10 * (int)((input % 1000) / 100) + (input % 10);
you will need 2 two input AND gates to do this. connect the output of the first to one input of the second. you now have a three input AND gate. just remember when calculating timing that 2 inputs of the 3 have twice the gate delay of the remaining input, thus the output will have skew and possibly glitches. if timing is critical or glitching can't be tolerated it may be best to use an actual three input AND instead of kludging one.
by analyzing your three input logic network
If you are talking combinations, without binary number representations, then you are talking about a circuit that has a 1 output when any input is a 0. That is a 3 input NAND gate. If you are talking binary number representation, then you are talking about a circuit that has a 1 output when the inputs are 010, 001, or 000. Use a 3 to 8 decoder, with an OR gate on the low three outputs.
There is no need for a combinatorial circuit to multiply a number by two. A binary number, left shifted one place, is twice the original binary number. The specific answer to the question is that you would connect the three input lines to the three high order output line of four output lines, and connect the low order bit of the four output lines to logic 0. If the three input lines were labelled A, B, and C, the output would be A, B, C, and 0.
input output and prosess
the electronic data processing consists of three stages which are the INPUT, the PROCESSING and the OUTPUT stages.
input, processing, output
True
If you look at the 7486 IC datasheet you can see, it have 4 independence XOR gates with 2 inputs. So you can only use 2 inputs if you see it like that. But if you understand the truth table of XOR gate you can have 3 input application using 7486 IC. Here I will show you how. 1.Get the first 2 input into the first XOR gate. 2.Then get the 3rd input together with the Output from the first 2 input XOR gate into another gate. 3.This output should be the result of 3 input XOR gate. Check this output with 3 input truth table to confirm the answer.
The three steps in processing information are input, processing, and output. Input involves receiving data or information, processing involves analyzing and interpreting the input, and output involves producing a response or result based on the processed information.
Input,Process,and Output
input/output units and processing unit
What? (Output Selection)How? (Input Selection)For Whom? (Distribution)