using a punnett square the parents would have to be Rr and rr
Punnett Squares are used to depict crosses of the parental or P generation and the possible offspring or F1 generation which can be formed from the traits being looked at which are represented by letters such as W for widow's peak, w for none, Y for yellow, y for green, so on and so forth. The diagrams depict the possibility of each offspring inheriting a specific/specific traits. Depending on the number of characteristics being looked at, the punnett square will range in size; the simplest is a 2x2 which states the possibility of offspring have 2 traits (2 traits of parents are being looked at; that is, whether or not parents have a characteristic/feature in relation to the possibility that their offspring will or will not). Ultimately, the outcomes depend on whether or not a trait is dominant, heterozygous, or recessive Dominant traits, represented by uppercase letters, generally overpowers the recessive traits which are represented by lowercase letters. Moreover, phenotypic and genotypic ratios can be found through Punnett Square crosses. Phenotypic ratios refer to the number of offspring with each specific physical characteristic/trait coded for by the different letter combinations and the genotypic ratios refer to the number of offspring with each different code. These ratios are separated by numbers and colons and begin at the top left corner of the square. Make sure to simplify if needed. For example: A homozygous dominant plant (RR) is crossed with a heterozygous round plant (Rr) --> RR x Rr RR x Rr: RR RR Rr Rr Phenotypic Ratio: 1 Round (100% chance of offspring being round) Genotypic Ratio: 1 RR: 1 Rr (50% chance of offspring being RR/Rr)
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
Mendel's pea plant experiments showed that at least two types of alleles (dominant, and recessive) must exist. Lets say for example that a red plant (for argument's sake, homo. dominant, RR) is crossed with a white plant (homo. recessive, rr). Most schools of thought at the time would have believed the result of this cross to be pink plants. This is true in some cases, but this was not what Mendel discovered.Instead, Mendel found the offspring to all the red. The reason?? All of the offspring were heterozygous, meaning they each had one dominant allele, and one recessive allele. (Rr) When this occurs, only the dominant form of the trait (in this case red) will be manifested.When a red plant and a white plant (for example) are crossed and yield a pink plant, the gene is considered to have "incomplete dominance". There is lots more to learn about simple genetics like this, most of which can be learned in a high school biology course as well as first year university biology. I suggest you check it out if you are still interested in learning more.
Because the possible combinations are DD, Dr, rD, and rr. When a dominant gene is present (D), then that gene is selected. The plants only have a one in four chance of getting a rr combo (r being recessive). It must inherit two recessive genes to display that trait.
The little r stands for a recessive wrinkled trait.
The genotype of the offspring that had the same phenotype as the parents is rr or wrinkled. The phenotype for the seed shape of both parent plants is round.
Let take the symbol for red trait "RR" for white "rr" for tall "TT" for short "tt" now as in case of incomplete dominance the red and white parents can give red, white and pink Rr incase of 4 o'clock plant now by crossing to short parents no progeny will be tall so the answer is no,we can not have offspring of red and tall with parents having pink and short traits, but there canb be red offspring with pink parents.
Rr
Punnett Squares are used to depict crosses of the parental or P generation and the possible offspring or F1 generation which can be formed from the traits being looked at which are represented by letters such as W for widow's peak, w for none, Y for yellow, y for green, so on and so forth. The diagrams depict the possibility of each offspring inheriting a specific/specific traits. Depending on the number of characteristics being looked at, the punnett square will range in size; the simplest is a 2x2 which states the possibility of offspring have 2 traits (2 traits of parents are being looked at; that is, whether or not parents have a characteristic/feature in relation to the possibility that their offspring will or will not). Ultimately, the outcomes depend on whether or not a trait is dominant, heterozygous, or recessive Dominant traits, represented by uppercase letters, generally overpowers the recessive traits which are represented by lowercase letters. Moreover, phenotypic and genotypic ratios can be found through Punnett Square crosses. Phenotypic ratios refer to the number of offspring with each specific physical characteristic/trait coded for by the different letter combinations and the genotypic ratios refer to the number of offspring with each different code. These ratios are separated by numbers and colons and begin at the top left corner of the square. Make sure to simplify if needed. For example: A homozygous dominant plant (RR) is crossed with a heterozygous round plant (Rr) --> RR x Rr RR x Rr: RR RR Rr Rr Phenotypic Ratio: 1 Round (100% chance of offspring being round) Genotypic Ratio: 1 RR: 1 Rr (50% chance of offspring being RR/Rr)
It is important to remember that the factors inherited by the first offspring of a cross have no effect at all on other offspring of that cross. For example, there is a 25% probability that offspring of a cross betweet two hybrid bean plants will inherit the factos RR. If one offspring inherits RR, there is still a 25% probability that the next offspring will also inherit RR.
R R r Rr Rr r Rr Rr That is the Punnet Square. The genotype will be 100% Rr in the cross. The phenotype will be whatever phenotype is constituted by your dominant allele.
All of the offspring will be red, since each of the four offspring receive the dominant red allele (R). Therefore, the offspring will all have the genotype Rr and a phenotype of red.
If red color is dominant, (RR) and white is recessive, (rr) then crossing a homozygous red plant with a homozygous white plant will produce 100% red offspring. This is the F1 generation. These F1 offspring will be 100% heterozygous (Rr). Subsequent crosses of these offspring in the second generation (F2) will produce 75% red and 25% white offspring phenotypically (the visual appearance of the color, The genotype ratio will 1 RR: 2 Rr:1rr with percentages of 25% homozygous red 50% heterozygous red and 25% homozygous white.
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
The backcross between a heterozygous (monohybrid) red flower plant (Rr) and a homozygous recessive white flower plant (rr) would produce a ratio of 1Rr:1rr. So you would expect half of the offspring to be red (Rr) and half the offspring to be white (rr).
Let us assume that both Rr and rr produce red flowers and only rr produces white flowers. Since one parents and the offspring are white, they have rr as genotypes. In order to achieve this result, the other parent would have to haev at least one r in its genotype. Since the otehr parent is red and needs to have one r, it's genotype is Rr. In short, the parents's genotypes are Rr for the red one and rr for the white one.
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr