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Actually copper has two common oxidation states, +1 and +2. However, we can leave that aside in discussing this question.

If we can assume that various atomic masses are known then a sample of a known mass of cupric oxide could be reduced with a known amount of hydrogen and the products weighed.

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Q: How do you know copper has a 2 charge?
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Related questions

What is the charge for CuO?

Since Oxygen has an ion charge of -2 & Copper has a 2 as a subscript, it means that Copper's ion charge will be +1. Cu2O = Copper (I) Oxide


What is the ionic charge of copper?

It is 1+ charge, but if they say copper (II), then that's 2+ charge.


What is the Neutral formula copper sulfate?

copper sulfate is CuSO4 and that in itself is neutral because the anion has a charge of -2 and copper has a charge of +2


What is the charge for copper hydroxide?

There is no charge. All compounds are electrically neutral. If you mean the charges of the component ions, copper carries a 2+ charge and the hydroxide ions carry a 1- charge.


What is the formula of copper 1 sulfate?

Copper sulfate has CuSO4 as its formula. Copper sulfate is also written copper (II) sulfate.


Is copper positively charged or negatively charged?

A copper ions has a positive charge, most commonly 2+.


When copper conbines with oxygen to form copper oxide the charge of the copper ion is?

+2


Why copper has 2 plus oxidation state?

i just know it because its in the 2nd group therefore is has 2 plus charge it also looses 2 electrons


What is the charge on the copper ion in the compound CuF2?

2+


What is the charge on the metal ion of the salt CuO?

As there are two of them, the charge on the copper ion is 1+ to balance the charge of the oxygen (2-).


What is the charge of copper2?

It's written Copper (II). The roman numeral is the charge on the metal, so the charge is +2.


What is the formula for (copper(1)sulfide)?

The formula for cuprous sulfide is Cu2S. Copper (I) or cuprous has a +1 charge, whereas Sulfur has a charge of -2. Cu^(-1) + S^(-2) -> Cu2S (The subscript is 2)