Actually copper has two common oxidation states, +1 and +2. However, we can leave that aside in discussing this question.
If we can assume that various atomic masses are known then a sample of a known mass of cupric oxide could be reduced with a known amount of hydrogen and the products weighed.
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Since Oxygen has an ion charge of -2 & Copper has a 2 as a subscript, it means that Copper's ion charge will be +1. Cu2O = Copper (I) Oxide
copper sulfate is CuSO4 and that in itself is neutral because the anion has a charge of -2 and copper has a charge of +2
There is no charge. All compounds are electrically neutral. If you mean the charges of the component ions, copper carries a 2+ charge and the hydroxide ions carry a 1- charge.
A copper ions has a positive charge, most commonly 2+.
i just know it because its in the 2nd group therefore is has 2 plus charge it also looses 2 electrons
Since Oxygen has an ion charge of -2 & Copper has a 2 as a subscript, it means that Copper's ion charge will be +1. Cu2O = Copper (I) Oxide
It is 1+ charge, but if they say copper (II), then that's 2+ charge.
copper sulfate is CuSO4 and that in itself is neutral because the anion has a charge of -2 and copper has a charge of +2
There is no charge. All compounds are electrically neutral. If you mean the charges of the component ions, copper carries a 2+ charge and the hydroxide ions carry a 1- charge.
Copper sulfate has CuSO4 as its formula. Copper sulfate is also written copper (II) sulfate.
A copper ions has a positive charge, most commonly 2+.
+2
i just know it because its in the 2nd group therefore is has 2 plus charge it also looses 2 electrons
2+
As there are two of them, the charge on the copper ion is 1+ to balance the charge of the oxygen (2-).
It's written Copper (II). The roman numeral is the charge on the metal, so the charge is +2.
The formula for cuprous sulfide is Cu2S. Copper (I) or cuprous has a +1 charge, whereas Sulfur has a charge of -2. Cu^(-1) + S^(-2) -> Cu2S (The subscript is 2)