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The presence of H+ ions, whereas basic solutions are basic because of the presence of OH- ions.
An acidic solution contains H+ ions, a basic solution contains OH- ions.
If a solution is basic it has how many ions
It's both really. Some ions are acidic, some are basic. Mostly, lye is in an acidic form though.
Acidic oxides generate H3O+ ions when mixed with water, while Basic oxides produce OH- ions.
The presence of H+ ions, whereas basic solutions are basic because of the presence of OH- ions.
An acidic solution contains H+ ions, a basic solution contains OH- ions.
Acidic.
If a solution is basic it has how many ions
It's both really. Some ions are acidic, some are basic. Mostly, lye is in an acidic form though.
Acidic oxides generate H3O+ ions when mixed with water, while Basic oxides produce OH- ions.
Because it contains sodium cations, which are strongly basic, and carbonate anions which are weakly acidic. So the basic ions win over acidic ions, making Na2CO3 alkaline(i.e. basic).
An acidic solution contains H+ ions, a basic solution contains OH- ions.
A pH test will tell you if it is acidic or basic. A pH test checks for the amount of H+ (hydromium) ions in solution. Higher amount of H+ ions means acidic, and higher amount of OH- means more basic.
You seem to be confused. acidic and basic are not things, they are properties. For example, vinegar is a solution, and it is acidic, because in solution, it dissolves to release hydrogen ions. Basic solutions, such as bleach, either accept hydronium ions in solution, or release hydroxide ions in solution. But all solutions, with the exception of distilled water, is either definatively acidic or basic. Look up a pH meter or a pH scale. The lower the number, the more acidic a solution is. The higher the number is, the more basic a solution is, and if it is 7.0, then it is neutral.
basic solutions have more bases in them, molecules that release 0H- ions in the solution. acidic solutions have more acids, molecules that give off H+ ions in the solution
No. It will be basic/alkaline.