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How do you prepare 1n hcl solution?

Updated: 8/10/2023
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8y ago

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You must take 88,8 mL concentrated HCL and fill up to 1000 mL with distilated water. (REMEMBER: ALWAYS ADD ACID TO WATER! - add 88.8mL to 900mL water and dilute to final volume = 1L)


The simplest and still pretty accurate answer would be based on the following things. The concentrated HCl means it is 12M. You can simpy use M1*V1=M2*V2 formula to calculate what You are looking for. In this case You do not have to worry switching from normal solution to molarity since 1M is = to 1 N for HCl.

Using M1*V1=M2*V2, where M stands for molarity and V for volume:

12M *X(unknown volume) ml (in mililiters) = 1 N (or 1M) * 1000 ml

1000 ml*M /12 M = 83.33(3) ml

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14y ago
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8y ago

The density of 36% HCl is not 1000 g/L. it is closer to 1.48 g/ml. 1000 g/L is the density of water.

using 1.48 g/ml means 100 ml would contain 148 g solution = .36x148 g HCl = 53.3 g HCl = 53.3 g / (36.5 g/mole) = 1.46 moles. if you dilute that to 1L you get 1.46 N HCl not 1N...

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this is the correct way to do this problem....

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let's use a 1000 ml volumetric flask. This will make 1000 ml of a 1N solution of HCl and will require this many grams of HCl

fyi. 1 N means 1 mole of equivalents per L solution and an equivalent is what we "chemists" and "chemical engineers" call an H+ ion or an OH- ion. HCl has 1 equivalent per molecule of HCl. H2SO4 has 2....

1000 ml solution x (1 mole equivalents / 1000 ml) x (1 mole HCl / 1 mole equivalents ) x (36.5 g HCl / mole HCl ) = 36.5 grams HCl. that's what you need in the flask to make your 1 N solution.

so how much of the 36% solution do you need? 36% by the way is based on mass. 36 g HCl / 100 g of solution....

so 36.5 g HCl x (100 g solution / 36 g HCl) = 101.39 grams solution.

the answer is about 100 grams. not 100 ml.... at 1.48 g/ml, 100 g = 100g x (1 ml / 1.48g) = 67.6 ml.....

*************** so make this solution this way ***********

read the temp requirement on the volumetric flask. fill the flask 1/2 full of distilled water. SLOWLY add 101.39 grams of your 36% HCl solution to the flask (put the flask on a balance, zero the balance, add the acid to 101.39g with a pipette if you want) . swirl the flask for a minute or so. add more water to about 90% of the way to the volumetric mark. cool the flask to the temperature indicated on it (like 25C) then fill the rest of the way to the mark with distilled water. then stopper it with a glass stopper and invert it several times to mix....
Use the equation: MaVa=MbVb

M= molarity V= volume

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15y ago

You must determine the concentration first of the concentrated HCl, typically concentrated HCl is a 36-38% HCL which works out to about 12-12.2 N concentration. From there all you have to due is dilute down to 0.1N. You must determine the concentration first of the concentrated HCl, typically concentrated HCl is a 36-38% HCL which works out to about 12-12.2 N concentration. From there all you have to due is dilute down to 0.1N.

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13y ago

You can prepare 0.01M HCl from 1M HCl by diluting it with water. To find the amount of water to dilute it with, we use the formula: M1V1=M2V2. If you need 100mL of the 0.01M acid, then we plug in the concentrations and volume:

(1M HCl)V1= (0.01M HCl)(100mL), and it solves to V1=1mL.

So, 1mL of 1M HCl diluted with 99mL water will make 100mL of 0.01M HCl.

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14y ago

Take specific volume of 3N solution and increase the volume three times by adding distilled water.

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11y ago

25 ml conc. Hcl(11.6 n)+91 ml distilled water

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How do you prepare the 10N HCl solution?

weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution. Reasons:N is short for NORMAL SOLUTIONS, The definition of a NORMAL SOLUTION is a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (replaceable H ions). eg:1N NaCl = 58.5 g/L 1N HCl = 36.5 g/L 1N H2S04 = 49 g/L Problems involving normality are worked the same as those involving molarity but the valence must be considered: 1N HCL the MW= 36.5 the EW = 36.5 and 1N would be 36.5g/L 1N H2SO4 the MW = 98 the EW = 49 and 1N would be 49 g/L 1N H3PO4 the MW = 98 the EW = 32.7 and 1N would be 32.7 g/L so,u can weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution.


How to prepare 1N HCl solution?

1N HCl is also 1M HCl because it is mono-protic. Therefore 36.5 g of HCl is required per liter or 3.65%. Simply take 100 g of 37% HCl and make up to the 1 liter mark on the volumetric flask. Check the value by titration against 1M NaOH. It should be perfect. If very slightly strong dilute very slightly (calculate) with water and re-standardize.


Calculaton of 1N HCl preparation?

take the Mr of HCl to be 36.46. to prepare 1.0M we should take 36.46g and dilute to a litre to prepare 0.10M we should take 3.646g and dilute to a litre From density =mass/volume, we get volume=mass/density. So ideally we should take that volume and dilute to a litre. However we know that most conc HCl solution are not 100% HCl. thus we must multiply that volume by a factor 100/x for an HCl solution labelled x% Tauya Chigayo


How do you prepare tris-hcl buffer solution of 0.5M?

6g Tris HCl + 100ml dH2O, pH 6.8


How to prepare HCL solution?

Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter

Related questions

How do you make 1N HCL from 1N HCL?

Take specific volume of 3N solution and increase the volume three times by adding distilled water.


How do you prepare 0.02 M of HCl?

Preparing 1N HCl for 1L. 1N=1M in HCl. Conc. HCl= 12M M1V1=M2V2 12*V1=1*1000 V1=1000/12 V1=83.33ml 1N HCl= 83.33ml of Conc. HCl in 1L of water 2N HCl= 167ml of Conc. HCl in 1L of water.


How do you prepare the 10N HCl solution?

weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution. Reasons:N is short for NORMAL SOLUTIONS, The definition of a NORMAL SOLUTION is a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (replaceable H ions). eg:1N NaCl = 58.5 g/L 1N HCl = 36.5 g/L 1N H2S04 = 49 g/L Problems involving normality are worked the same as those involving molarity but the valence must be considered: 1N HCL the MW= 36.5 the EW = 36.5 and 1N would be 36.5g/L 1N H2SO4 the MW = 98 the EW = 49 and 1N would be 49 g/L 1N H3PO4 the MW = 98 the EW = 32.7 and 1N would be 32.7 g/L so,u can weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution.


How to prepare 1N HCl solution?

1N HCl is also 1M HCl because it is mono-protic. Therefore 36.5 g of HCl is required per liter or 3.65%. Simply take 100 g of 37% HCl and make up to the 1 liter mark on the volumetric flask. Check the value by titration against 1M NaOH. It should be perfect. If very slightly strong dilute very slightly (calculate) with water and re-standardize.


Calculaton of 1N HCl preparation?

take the Mr of HCl to be 36.46. to prepare 1.0M we should take 36.46g and dilute to a litre to prepare 0.10M we should take 3.646g and dilute to a litre From density =mass/volume, we get volume=mass/density. So ideally we should take that volume and dilute to a litre. However we know that most conc HCl solution are not 100% HCl. thus we must multiply that volume by a factor 100/x for an HCl solution labelled x% Tauya Chigayo


How do you prepare 1N Hcl solution Dont tell in gL how much ml is required?

1N HCL is the same as 1 Molar HCl. You take the # of H ions and multiply by the molarity to get the Normality. Usually you buy HCl in concentrated form which is 12 Molar or 12 Normal HCL. You need to dilute the concentrated HCl to get the reduced concentration. Use the formula Molarity Initial x Volume Initial = Molarity Final x Volume Final ex. 12 M HCL x 10 ml = 1 M x 120 ml. So take 10 ml of concentrated HCl and add enough water to make 120 ml. This will give you 120 ml of 1 M (which is 1N) HCl. Venkat Reddy


How do you prepare 1n solution?

Dissolve 1.0 mole gas (17 gram) in 1.0 Liter water


How do you prepare tris-hcl buffer solution of 0.5M?

6g Tris HCl + 100ml dH2O, pH 6.8


How do you prepare 5N hcl solution?

520 ml of HCl in 480 ml of water=1000ml = 5 N


How to prepare HCL solution?

Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter


Why do you find acid normality why dont you take known normality of acid?

Acid solutions are typically made in laboratories from commercially available acids which are supplied with specifications as to their physical and chemical properties including their concentrations. Calculations: For example, if you wish to use concentrated HCl that just arrived in your lab yesterday to make (say) 1N HCl, you will need to know the normality of the available solution. Suppose you know that it is 37% HCl (and all other information is missing); this means 37 mL HCl in 100 mL solution, M.W. of HCl = 36.5, Density = 1.185; 1.185 g HCl occupies 1 mL volume, 37 mL HCl corresponds to 43.84 g HCl. If the commercially available solution is 43.84 g HCl in 100 mL solution and you know that 36.5 g HCl in 1000 mL solution makes 1N (also 1M HCl) solution, then you have a 12N (also 12M) solution in your hands. So that means you must dilute it 12 times to get a 1N HCl solution. Titration: If you don't have a new solution at hand and are not sure about how correctly the HCl reagent was stored over many years, it would be prudent to measure the concentration of acid by titration provided you have fresh (reliable) base solutions at hand and reliable indicators.


How do you prepare 1n AMMONIA solution?

Dissolve 1.0 mole gas (17 gram) in 1.0 Liter water