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To convert make a dillute solution from a concentrated one, take the amount of moles needed for the final solution as mL of concetrated solution, and dillute with water until the desired volume is reached.

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Q: How do you make 60 mL of a 0.1 M HCl solution from 6.0 M HCl?
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How much of a 2 mole NaOH solution would be required to neutralize 20mL of a 6 mole HCl solution?

I assume you mean molar instead of mole?Fast:The HCl solution is 3 times as concentrated.Since both can only donate 1 H+ or OH-...you wil need 3 times as much NaOH to neutralise the HCl.20 ml * 3 = 60 mlSlow:The HCl solution has 6 mol/LThere is 20 ml of it, so you have 0.02 L * 6 mol/L = 0.12 mol of HClEach mole of HCl donates 1 mole of H+So there is 0.12 mol of H+ that you have to neutralise.This equals to 0.12 mol OH-Each NaOH donates 1 OH-So you need 0.12 mol NaOHThe NaOH solution you are using has 2 mol/LSo you have to use 0.12 mol / 2 mol/L = 0.06 L = 60 ml


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