I assume you mean molar instead of mole?
Fast:
The HCl solution is 3 times as concentrated.
Since both can only donate 1 H+ or OH-...
you wil need 3 times as much NaOH to neutralise the HCl.
20 ml * 3 = 60 ml
Slow:
The HCl solution has 6 mol/L
There is 20 ml of it, so you have 0.02 L * 6 mol/L = 0.12 mol of HCl
Each mole of HCl donates 1 mole of H+
So there is 0.12 mol of H+ that you have to neutralise.
This equals to 0.12 mol OH-
Each NaOH donates 1 OH-
So you need 0.12 mol NaOH
The NaOH solution you are using has 2 mol/L
So you have to use 0.12 mol / 2 mol/L = 0.06 L = 60 ml
The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution cheers :D The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution.
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16ml of 0.1M sodium hydroxide solution needs 20ml of 0.08M sulfuric acid to reach end point.
Use the formula C1(V1) = C1(V2) to find the unknown concentration. Here, V1 = 20ml and V2 = 33.86ml. Also, C2 is 0.1368M Now plug in these values to find V1 Therefore we have: 20ml(V1) = (0.1368)(33.86) Therefore, V1 = 0.2316M The a 0.2316M solution of H2SO4 was required for the neutralization reaction
The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution cheers :D The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution.
A mL and a cc are the exact same. So if you have 20mL, you have 20cc.
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first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
put 20ml of water with two teaspoonsfull of glucose.You will get your mixture ready
20ml
20ml - 0.2ml = 19.8
A measuring cylinder
The three coins would have a volume of 33ml. This can be seen from the simple calculation: 53ml - 20ml = 33ml.
Xml/1gm=100mL/5g=20mL Xgm/10mL=5gm/100mL=.5gm =.5g/20mL