Corrected: (Sodium is not the same as sodium chloride)
0,1 grams Na+ in 1 liter water. This amount of sodium (Na+) is present in
0.1 (g Na+) * [ 58.45 (g/mol NaCl) / 22.99 (g/mol Na+) ] = 0.2542 g NaCl = 0.25 g/L
1. Weigh 100 mg ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask using a funnel. 3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.
I prefer my brine with a lot more salt than that.
Dissolve 1 g NaCl p.a. in 1 L demineralized water, at 20 0C, in a volumetric flask.
Dissolve 100 mg sodium chloride in 1 L demineralized water.
One mole solution of sodium chloride makes 1000 millimole. So 0.1 mole solution of sodium chloride will have 100 millimole in the solution.
100 g of the solution contains 11 g of sodium chloride
100ml is 0.1 litres, so you need 0.1 moles of sodium chloride.
The answer is: 0,9 g NaCl in 100 g solution.
Hayem's solution. This is an isotonic fluid which consists of the folIowing constituents (in g/100 ml):sodium chloride 0.5, sodium sulphate 2.5 and mercuric chloride 0.25. The sodium sulphate discourages clumping of the erythrocytes and the mercuric chloride is a preservative.
This is a solution containing 100 mg NaCl/L.
This is a water solution containing 5 g dextrose and 0,3 g sodium chloride in 100 mL.
Divide the amount of sodium chloride by the total amount (sodium chloride + water). Then multiply that by 100 to convert to percent.
Dissolve 30g of sodium chloride in 100 mL of water.
0.9% means there is 0.9 grams NaCl per 100ml of solution. So 1000 ml of 0.9% sodium chloride contains 9.0 grams of NaCl.
Hypernatremia is treated with infusions of a solution of water containing 0.9% sodium chloride (0.9 grams NaCl/100 ml water), which is the normal concentration of sodium chloride in the blood plasma