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What is the molarity of 67.94 mL aqueous solution containing 2.822 g of KI?
Molarity = moles of solute/Liters of solution. get moles KI 2.822 grams KI (1 mole KI/166 grams) = 0.017 moles KI ( 67.94 ml = 0.06794 Liters ) Molarity = 0.017 moles KI/0.06794 Liters = 0.2502 M KI
What mass of KI is present in 276 mL of a 0.50 M solution?
V*c*M = 276(mL)*0.001(L/mL)*0.50(mol KI/L)*166.0(g KI/mol KI) = 22.9 g KI
Why KI is to be added to prepare to prepare iodine solution?
KI is potassium iodide, you'd react it with something to produce iodine ions. It reacts as reducing agent
How many moles of KI are present in 500 ml of a 0.2M solution?
The answer is 0,1 mol.
Is SnI4 soluble in KI solution?
Hi, having a solution of KI implies having H20 so tin iodide will hydrolyze forming the tin oxide and HI. Another interesting reaction is when you add KI (in solid phase) into tin iodide solution (dissolved in acetone). You will obtain a salt like this: K(SnI5) I hope I helped you. Note that this answer could be wrong, I'm currently a student of chemistry and I have a lot to learn yet.
How do you prepare a 10 percent potassium iodide solution?
Take 10 gm oF KI dissolve it in 100ml.
To 225 mL of a 0.80M solution of KI a student adds enough water to make 1.0 L of a more dilute KI solution What is the molarity of the new solution?
0.18M
What is the molarity of 67.94 mL aqueous solution containing 2.822 g of KI?
Molarity = moles of solute/Liters of solution. get moles KI 2.822 grams KI (1 mole KI/166 grams) = 0.017 moles KI ( 67.94 ml = 0.06794 Liters ) Molarity = 0.017 moles KI/0.06794 Liters = 0.2502 M KI
How many grams of KI are in 25.0ml of a 3.0 (mv) KI solution?
55 ml of a 4.05 M solution of KI solution contains 55*4.05=222.75 millimoles. 20.5 ml of the diluted solution contains 3.8g of KI,so no.of moles of KI=3.8/(mol.wt of KI=165.9) is 22.9 millimoles. molarity of final diluted solution=22.9/20.5=1.117M since the no. of moles of KI present in initial and final solution are same. let.V(in ml) be the final volume of diluted solution. 222.75/V=1.117 V=199.41 ml final volume =199.41 ml
What is the molarity of a solution prepared by dissolving 2.41 g of potassium iodide KI in 100 mL of water?
Find moles potassium iodide first.2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KIMolarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )Molarity = 0.01452 moles KI/0.1 Liters= 0.145 M KI solution================
How do you prepare iodine solution?
dissolve iodine crystals in a saturated KI(potassium iodide) solution
What mass of KI is present in 276 mL of a 0.50 M solution?
V*c*M = 276(mL)*0.001(L/mL)*0.50(mol KI/L)*166.0(g KI/mol KI) = 22.9 g KI
Is kI is a acid?
KI or potassium iodide will be basic in solution because it is the product of KOH (a strong base) and HI (a weak acid.)
When was Inochi no Ki created?
Inochi no Ki was created on 2010-10-06.
When was Haroon Ki Awaz created?
Haroon Ki Awaz was created in 2000-10.
When was Jannat Ki Talash created?
Jannat Ki Talash was created on 1999-10-24.
When was Lee Ki-Chan born?
Lee Ki-Chan was born on 1979-01-10.
