First you take a lond string and attach it to your arm then you get bouncy ball and add it to you Arm, now you have an Rigid Arm Pendulum.
Answering "A simple 2.80 m long pendulum oscillates in a location where g9.80ms2 how many complete oscillations dopes this pendulum make in 6 minutes
You need to give more info than simply "rigid pipe". What kind of "rigid pipe", what pressure will it have and where you are burying it.
Yes. Carbon is added to iron in steel to make the steel stronger by making it more rigid. The more rigid a metal is, the less malleable it is.
make the rod longer the rod will shorten the period. The mass of the bob does not affect the period. You could also increase the gravitational pull.
What is the difference between rigid and flexible coupling.
The pendulum has an arm length of 0.06 meters or 2.36 inches.
Assuming the pendulum referred to s asimple pendulum of an arm and a weight the major factors on the period are the local attraction of gravity and the length of the arm.
the period T of a rigid-body compound pendulum for small angles is given byT=2π√I/mgRwhere I is the moment of inertia of the pendulum about the pivot point, m is the mass of the pendulum, and R is the distance between the pivot point and the center of mass of the pendulum.For example, for a pendulum made of a rigid uniform rod of length L pivoted at its end, I = (1/3)mL2. The center of mass is located in the center of the rod, so R = L/2. Substituting these values into the above equation gives T = 2π√2L/3g. This shows that a rigid rod pendulum has the same period as a simple pendulum of 2/3 its length.
the longer you make the pendulum arm the longer it will take to perform its swing,the same thing would happen if you only increased the weight on the end of the arm.
Answer: The combined inertia of the arm and pendulum would alter the energy characteristics of the system and throw off the timing. Answer: If the mass of the arm is not negligible, then you can no longer assume (as in an ideal pendulum) that the entire mass is concentrated in the swinging object at the bottom. The center of mass would be higher up. Exactly how high depends on the characteristics of the pendulum; details can be calculated with integral calculus.
That's an "idealized" pendulum, which is completely rigid, and where all the mass is concentrated in the bob, which is considered to be pointlike.
By shorten the string of the pendulum
true or false a good archer keeps his or her body and arm tense and rigid at all times
The generalized coordinate for the pendulum is the angle of the arm off vertical, theta. Theta is 0 when the pendulum arm is down and pi when the arm is up. M = mass of pendulum L = length of pendulum arm g = acceleration of gravity \theta = angle of pendulum arm off vertical \dot{\theta} = time derivative of \theta What are the kinetic and potential energies? Kinetic energy: T = (1/2)*M*(L*\dot{\theta})^2 Potential energy: V' = MLg(1-cos(\theta)) V = -MLg*cos(\theta) --note: we can shift the potential by any constant, so lets choose to drop the MLg The Lagrangian is L=T-V: L = (1/2)ML^2\dot{\theta}^2 + MLg*cos(\theta)
Fulcrum.
You make a pendulum with a basbeall attached to an end of the string. you are testing the periods and oscillation movements of the pendulum.
If the plumb point of a pendulum is the center of earth, the pendulum will make diametrical oscillations