One way to make an eight input AND gate out of transistors...
Start with one transistor, NPN. Ground the emitter. Connect the collector to Vcc with a resistor. Connect the base to Vcc through two resistors, picked to drive the transistor into saturation. The input of that stage is the junction of the two resistors. If you ground that input, the transistor cuts off, and the collector goes high. Unground the input, and the collector goes low.
OK. Now you have an inverter.
Build eight of them, but only use one collector resistor, and tie all of the collectors together. If any one input is high, the output is low. If all inputs are low, the output is high.
OK. Now you have an 8 input negative logic NAND gate.
Follow it up with another inverter stage, reversing the output.
OK. Now you still have an 8 input NAND gate, with the output high true.
If you want the inputs to be high true also, connect each one to an inverter. This will use 17 transistors, and you will have an 8 input positive logic AND gate.
You would connect the output of the first AND gate to one input of the second AND gate. You are left with 2 inputs on the first AND gate and 1 input on the second AND gate. The final output is from the second AND gate.
Tie unused input high through pullup resistor.
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NOR gate = not(A or B) = A nor BAND gate = A and BAND gate = not(not A or not B)AND gate = not(not(A or A) or not(B or B))AND gate = (A nor A) nor (B nor B)Therefore using 2 input NORs to make a 2 input AND you need three NORs. If you wanted something different (e.g. a 5 input AND) the above proof can be modified appropriately to get your answer.
Well, if you mean to make the truths of an AND gate similiar to the ones of OR gates, then you can do the following: 1. Put an inverter at every input of the AND gate. This will make it act like an NOR gate 2. Put an inverter at the output of the gate. This will invert the truths and turn the NOR gate into an OR gate
Transistors can be structured to create logic gates by connecting them in specific configurations that represent logical functions. For example, a NOT gate can be formed using a single transistor, while AND and OR gates typically require a combination of two or more transistors arranged in series or parallel. By controlling the flow of current through these transistors based on input signals, the gates can produce corresponding output signals that reflect the desired logical operation. This arrangement allows for the construction of complex circuits capable of performing various computational tasks.
for a two input gate to represent as an n-input gate excatly n-1 two input gates are required. this implies that for a two input OR gate to represent a four input OR gate exactly three two input OR gates are required let F is =a+b+c+d =(((a+b)+c)+d) =((a+b)+(c+d)) in both the above cases + is used three times so three two input OR gates make a four input OR gates. This discussion doesnot hold good for NAND gates an example can illlustrate the reson:- take F=(a.b.c.d)'=a'+b'+c'+d' --------------------------->(1) (this is obtained by a four input NAND gate) let us take this in the manner we did it for an OR gate and we will then verify the result. =((a.b)'(c.d)')' =((a'+b').(c'+d'))' =(a'+b')'+(c'+d')' =ab+cd <------------------------(2) (1)is not equal to (2) so we can say that a NAND gate cannot be replaced in the manner as OR gate is replaced
You can't make XOR out of NOT alone. Mathematically, NOT takes only a single argument, and its gate, an inverter, takes a single input. There's no way to combine two inputs giving a single output with one input gates. You need some two input gates to do the job. They can be AND, OR, NAND, NOR, or some combination, but you need something. That said, they don't have to be IC gates; you can combine two inputs with diodes to make an OR gate, so you could make XOR with only inverters and diodes, i.e. no other gate symbols on your schematic, but it would mot be making XOR out of NOT.
the easiest way to make an xnor gate is with a 7486 (or equivalent) integrated circuit, a quad xor gate. connect the output of one gate to one in put of another gate. connect the other input of the second gate to Vcc. the second xor gate will then act as an inverter.
A: NOT means inversion of the function like an OR gate if inverted it becomes a NOR gate AND becomes a NAND gate if logic input function is inverted on the output. This can plainly be seen by looking at a gate symbol if there is a circle on the output it means it function is inverted.B: You have not answered my question, please read carefully my question again!
The NAND gate has two or more inputs, and one output. This output is the complement of the AND of all the bits and will only be 0 if all the inputs are 1.A NOT gate on the other hand has only 1 input, and the output is the complement of this input.So to make a NAND gate into a NOT gate, we should tie (short, connect to same value) all the inputs of the NAND gate. At the output we would have the complement of the signal given at the tied inputs.This way we have a NOT gate from a NAND gate.
Short answer: An IC is a "Integrated Chip". An OrGate is a 2 (or more) input chip with onlt 1 output. Longer answer: IC stands for Integrated Circuit, we call them "Chips" and they have multiple electronic devices integrated into them like resistors, transistors, capacitors, all in one package to make monolithic circuit package, to form everything from AndGates, OrGates, NorGates, ExOrGates, Buffers, to microprocessors and more. an Or Gate is a digital divice with two or more INPUTS that will produce a digital OUTPUT depending on the input, if one OR the other inputs have an inupt of 1 the output will be 1 otherwise it will be 0. they are used to make "logic" and "arithmetic circuits" from calculators to computers to network cards and routers and much more.