You have to dilute the 10 mM NaCl 100X, 33,333X and 10X (X means "times") e.g. 100X: mix 10 ml of 10 mM Nacl with 990 ml of water (= 0,1 mM) 33,333X: mix 30 ml of 10 mM NaCl with 970 ml of water (= 0,3 mM) 10X: mix 100 ml of 10 mM NaCl with 900 ml of water (= 1 mM)
Dissolve 100 mg NaCl in 1.0 Litre water.
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
Dissolve 30g of sodium chloride in 100 mL of water.
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
Dissolve 100 mg NaCl in 1.0 Litre water.
Dissolve 2g of NaCl in 100 cm3 water at normal temperature.
To prepare a 0.9% solution take 0.9grams NaCl and dilute with 100mls of water.
The volume is 342 mL.
By a slowly evaporation of water from a NaCl solution.
Molarity of 1X PBS is 10mM. To prepare 20mM PBS take 16g of NaCl, 0.4 g KCl, 2.88 g Na2HPO4 0.48 g KH2PO4 in 800 ml of distilled H2O. Adjust the pH to 7.4 with HCl. Add H2O to 1 liter.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
Dissolve 16,61 g NaCl analytical reagent, dried in 1 L of demineralized water at 20 0C, in a volumetric flask.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Sodium chloride is the result of this reaction: NaOH + HCl = NaCl + H2O
Reactions are: 2Na + Cl2 = 2NaCl NaOH + HCl = NaCl + H2O
A method is the following:NH4Cl + NaNO2 = N2 + NaCl + 2 H2O