0
0.4 M means 0.4 moles in 1 litre of water.
For Na2CO3 first calcultate the Relative Molecular Mass (Mr) from the Periodic Tabler.
2 x Na = 2 x 23 = 46
1 x C = 1 x 12 = 12
3 x O = 3 x 16 = 48
46 + 12 + 48 = 106
Next using the equation Moles = mass(g) / Mr
Algebraically rearrange
mass(g) = moles X Mr
mass ( g) = 0.4 X 106
mass( g) = 42.4 g
Weigh this amount out on a lab balance.
The dissolve in 500 mL of water.
When fully dissolved make the volume of the solution up to 1000 mL ( 1 litre) using distilled water.
NB Do NOT dissolve in 1000 mL(1 litre) as the volume in total will be greater than 1 litre, and it will not be 0.4 M , but a lesser value. Dissolve in less than 1 litre and make up to 1 litre with more distilled water.
NNB Finally, please write your chemical symbols correctly, 'Co' os the symbol for 'Cobalt'. For the Carbonate is is 'CO3'. Note the use of capitals.
Hope that helps!!!!
lenpollock
To prepare 0.4M Na2CO3 solution, dissolve 15.6g of Na2CO3 in water and make up to 1 liter of solution. Make sure to use a balance to accurately measure the mass of Na2CO3 and a volumetric flask to prepare the final volume.
Wiki User
∙ 11y ago4.24 gm Na2CO3 IN 100 D.W.
Add your answer:
Earn +20 pts
How do you prepare standard 0.1 N 100 ml Na2CO3 solution?
To prepare a 0.1 N 100 ml Na2CO3 solution, dissolve 5.3 grams of Na2CO3 in water and dilute to 100 ml. This will give you a solution with a concentration of 0.1 normal (N) for the 100 ml volume.
Standardization of hcl solution with primary standard na2co3 solution?
To standardize an HCl solution with a primary standard Na2CO3 solution, first, prepare a Na2CO3 solution of known concentration. Then, titrate the Na2CO3 solution with the HCl solution using a suitable indicator until the equivalence point is reached. From the volume of HCl solution used and the known concentration of Na2CO3, you can calculate the exact concentration of the HCl solution.
Why was 1.06 g of Na2 CO3 added to 1 liter if water to prepare a 0.02 n solution?
1.06 g of Na2CO3 was added to 1 liter of water to prepare a 0.02 N (normality) solution because that specific mass of Na2CO3 provides the required molarity of Na+ ions in the solution. Normality is a measure of concentration that relates to the equivalents of a substance rather than the moles, and in the case of Na2CO3, it is important to account for the stoichiometry of the compound to achieve the desired concentration.
What mass is required to make 2N solution of Na2co3 calculate mass of sodim carbonate which will be dissolved in 500 ccc?
To prepare a 2N solution of Na2CO3 in 500 mL, you would need to dissolve 42.97 grams of Na2CO3. This is calculated by first converting N to molarity (2N = 2 moles/L), then using the molar mass of Na2CO3 (105.99 g/mol) to calculate the required mass.
How do you prepare 250ml 15m solution of naco3 in a volumetric flask do presume a solvent ie h20 but then you have to presume volumes and conc and because 15M wanted you cant use the flask to dilute?
To prepare a 250ml 15M NaCO3 solution in a volumetric flask without using the flask to dilute, you would first calculate the mass of NaCO3 needed based on its molar mass. Then, dissolve this mass in a small volume of water in a separate container and transfer it quantitatively to the 250ml volumetric flask, and then add enough water to make up to the mark. Finally, mix thoroughly to ensure homogeneous distribution.
How washing soda is prepared?
10 molecule of water is added to one molecule of Sodium carbonate to prepare washing soda. Na2CO3+10 H2O= Na2CO3 . 10 H2O
Why was 1.06 g of Na2 CO3 added to 1 liter if water to prepare a 0.02 n solution?
1.06 g of Na2CO3 was added to 1 liter of water to prepare a 0.02 N (normality) solution because that specific mass of Na2CO3 provides the required molarity of Na+ ions in the solution. Normality is a measure of concentration that relates to the equivalents of a substance rather than the moles, and in the case of Na2CO3, it is important to account for the stoichiometry of the compound to achieve the desired concentration.
What are the merits and advantages of solvay's process?
The ingredients for the process are easily available and inexpensive.
How are 0.50m Na2CO3 and 0.50M Na2CO3 different?
difference between 0.50mol na2co3 anf 0.50 M of na2co3
How do you prepare 250ml 15m solution of naco3 in a volumetric flask do presume a solvent ie h20 but then you have to presume volumes and conc and because 15M wanted you cant use the flask to dilute?
To prepare a 250ml 15M NaCO3 solution in a volumetric flask without using the flask to dilute, you would first calculate the mass of NaCO3 needed based on its molar mass. Then, dissolve this mass in a small volume of water in a separate container and transfer it quantitatively to the 250ml volumetric flask, and then add enough water to make up to the mark. Finally, mix thoroughly to ensure homogeneous distribution.
Sodium carbonate equation?
The chemical equation for sodium carbonate is Na2CO3. It is made up of two sodium atoms, one carbon atom, and three oxygen atoms. When dissolved in water, it dissociates into sodium ions (Na+) and carbonate ions (CO3^2-).
Chemical formula of washing soda?
The chemical formula for washing soda is Na2CO3, which represents the compound sodium carbonate.
What is the AR or MR value of Co2 and NA2CO3?
The AR (atomic mass) of CO2 (carbon dioxide) is 44 g/mol. The MR (molar mass) of Na2CO3 (sodium carbonate) is 106 g/mol.
What is the balanced equation of the reactants MnSO4 and Na2CO3?
The balanced equation for the reaction between MnSO4 and Na2CO3 is: MnSO4 + Na2CO3 -> MnCO3 + Na2SO4.
How many grams are in 0.577 mol Na2CO3?
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
How many moles of washing soda are there in 5g?
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
What is the KB of Na2CO3?
The molar mass of Na2CO3 (sodium carbonate) is approximately 105.99 g/mol. To calculate the KB, you would first look up the pKa values for the conjugate acid (HCO3-) and then use the relation KB = Kw / Ka.
