How do you prepare 0.85m sucrose solution?
how to prepare a concentration of 100 ug/ml limonin
A solution is prepared by dissolving 125g of sucrose C12 H22 O11 in whater to prepare 1.00L of solution What is the molarity of the solution?
Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In…
N should be M, meaning number of mole (N) per litre. Concentration equals the number of mole per litre, or simply C=N/V. We know the concentration is 0.1 mol/L One mole of sucrose = 342g (from the molecular formula C12H22O11) so 0.1 mol = 34.2g. To make a 0.1 M sucrose solution, mix 34.2 grams of sucrose into every litre of water.
If 1 mole of sucrose equals 342.12 grams of sucrose plus 1000 mL of water then how can you calculate the amount of water and sucrose in 0.2 moles of sucrose?
I am assuming you are refering to a one molar solution. I am also assuming that you have simplified the problem, because sucrose takes up space in water, so a 1 molar solution of sucrose would have less than 1000mL of water. I do not know the what volume of solution is desired, so I will use one liter in my equation. For the sake of organization: 1L sucrose solution * (0.2 moles sucrose/ 1L)…
If a sucrose solution contains 15g of sucrose per every 100ml of solution how many grams of sucrose are there in 3.0L of sucrose solution?
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
It is a solute that causes osmosis to occur. For instance, if a solution contains sucrose and the membrane is impermeable to sucrose,, water will move out of the cell and into the solution to dilute it. Hence the solution is hypertonic. Sucrose would be considered an osmotically active solution in this case because it induces osmosis of water across a membrane.
Why is it that when you put a potato in a high concentration of sucrose solution does its weight decrease?
This is because the potato, which is mostly water, is in a hypertonic solution (a solution with less water and more solute --here, sucrose-- than the potato). Since the solutions want to reach equilibrium (equal amounts of sucrose and water in both the solution and the potato), water diffuses out of the potato and sucrose diffuses into it. The potato loses its water weight, and sucrose doesn't replace the weight lost, the potato weighs less.
How do you identify three sugar solutions which the first one contains glucose then second one is a mixture of glucose and sucrose and lastly is sucrose solution?
Easy. Just use Benedict's solution. In glucose solution it would give a brick red precipitate. In sucrose solution, there would be NO brick red precipitate. If there is a mixture of sucrose and glucose solution, the the solution would react to give a red solution or perhaps a solution with LESS brick red precipitate than the glucose solution. When carrying the above procedure, ensure the volume and concentration of the solutions used for the test…
molarity (M) = moles/litre of solution To make a 1.0 M sucrose solution, you need the molar mass of sucrose. C12H22O11 (12x12.0) + (22x1.0) + (11x16.0) = (according to wikipedia 342.30 g/mole) Take the 342.20 grams of sucrose and put it into a graduated cylinder and then fill to the 1.0 L mark with water.