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to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
- Weight 0,4 g of NaOH - Transfer the granules in a 1 L volumetric flask - Add 9oo mL distilled water; maintain the flask in a thermostat at 20 0C, for min. half hour - Add distilled water up to the mark - Stir the content To know the correct concentration this solution must be titrated with an acid.
a solution of 0.1M NaOH has been prepared.How would you make 1L of the same solution
1. Weigh 20 g NaOH. 2. Put this NaOH in a 1 L volumetric flask. 3. Add slowly 200 mL distilled water and stir. 4. Put the flask in a thermostat at 20 0C and maintain for 1 hour. 5. Add distilled water up to the mark. Stir vigorously. 6. Standardize the solution by titration with oxalic acid, potassium hydrogen phtalate, etc. 7. Transfer the solution in a bottle and apply a label (date, name of the operator, name of the solution, normality).
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
add 10 grams of NaoH into 1000 ml water, it will give you NaoH of 0.25N. As for making 1N solution you need to disolve 40 grams of NaoH into 1 litre water.
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
If you think to a 2 M solution dissolve 80 g NaOH in 1 L demineralized water at 20 0C.
You must know the method and not just the answer. Think about this problem: What does 5% mean? It tells you that for every 100g (or ml) water, you must have 5g of NaOH. You have 235 ml water. Therefore you will have to use more NaOH. You can calculate this as follows: (235/100)*5= 11.75g NaOH
- Weight 0,4 g of NaOH - Transfer the granules in a 1 L volumetric flask - Add 9oo mL distilled water; maintain the flask in a thermostat at 20 0C, for min. half hour - Add distilled water up to the mark - Stir the content To know the correct concentration this solution must be titrated with an acid.
a solution of 0.1M NaOH has been prepared.How would you make 1L of the same solution
1. Weigh 20 g NaOH. 2. Put this NaOH in a 1 L volumetric flask. 3. Add slowly 200 mL distilled water and stir. 4. Put the flask in a thermostat at 20 0C and maintain for 1 hour. 5. Add distilled water up to the mark. Stir vigorously. 6. Standardize the solution by titration with oxalic acid, potassium hydrogen phtalate, etc. 7. Transfer the solution in a bottle and apply a label (date, name of the operator, name of the solution, normality).
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)