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1. Weigh 58,4 mg ultrapure NaCl dried at 110 0C for 30 min.

2. Transfer NaCl in a clean 1 L volumetric flask using a funnel.

3. Wash the funnel with 0,9 L demineralized water.

4. Put the flask in a thermostat and maintain 30 min at 20 0C.

5. Add demineralized water up to the mark.

6. Stir vigorously and transfer in a clean bottle with stopper.

7. Add a label with necessary information.

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8y ago

Dissolve 116,88 g NaCl in 2 L water.

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Q: How do you prepare 2 liter of 1m sodium chloride?
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How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?

Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V


How much sodium chloride is required to make 1litre of 1M solution?

0.056g


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A 1M solution of sodium carbonate contains 1 gram formula mass of sodium carbonate dissolved in each liter of solution.


Which phase will be on top in an immiscible mixture of methylene chloride and 1M of sodium hydroxide?

Sodium hydroxide solution will be on the top.


What is produced at the cathode of an electrolytic cell containing 1M solution of sodium chloride?

Chlorine gas. Cl2


Ionic formula for sodium chloride?

The ions in sodium chloride are Na+1 and Cl-1.


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How do you prepare 1M sodium phosphate dibasic?

sodium phosphate dibasic means that there are two sodium molecules in the formula (contributing to two bases). the formula is Na2HPO4. the first step is to figure out the molecular weight of the compount with the help of a periodic table. This comes out to 142g/mole. To make 1M solution (M= moles/liter so I am assuming 1 liter) you need 142 grams of the compound in 1L of dH2o. The definition of molarity (which is moles over liters) makes the calculation easy for making 1L of the solution. However if you want to make less or more of the solution, you will have to calculate accordingly. For example if you wanted to make 50 ml (0.05L) of the solution, you would multiply 142 g/liter (g/mol x moles/liter will give g/liter) X 0.05 liter, which would give you 7.1 g. 7.1 g of Na2HPO4 is needed to make 50 ml of 1 M solution. 142 g is needed to make 1000ml (1 L) of 1M solution.


How can we prepare 1M solution of NaCl?

You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.


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How do you prepare 10mM Tris?

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How many molecules of NaCl are in the 1 M NaCl solution?

It depends on how much solution you have!"1 molar solution" means that 1 litre of the solution contains 1 mole of solute (in this case, Na+ and Cl- ions). Therefore, 1 litre of 1M NaCl will contain 1 mole of sodium chloride. 1 mole is avagadro's number (6.02x1023) of a substance. If you have two litres of solution, obviously, you will have twice this number, for example.Note, though, that there are NO molecules of sodium chloride - sodium chloride is not a molecular substance.