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sodium phosphate dibasic means that there are two sodium molecules in the formula (contributing to two bases). the formula is Na2HPO4. the first step is to figure out the molecular weight of the compount with the help of a Periodic Table. This comes out to 142g/mole. To make 1M solution (M= moles/liter so I am assuming 1 liter) you need 142 grams of the compound in 1L of dH2o. The definition of molarity (which is moles over liters) makes the calculation easy for making 1L of the solution. However if you want to make less or more of the solution, you will have to calculate accordingly. For example if you wanted to make 50 ml (0.05L) of the solution, you would multiply 142 g/liter (g/mol x moles/liter will give g/liter) X 0.05 liter, which would give you 7.1 g. 7.1 g of Na2HPO4 is needed to make 50 ml of 1 M solution. 142 g is needed to make 1000ml (1 L) of 1M solution.
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What does 1M solution of sodium carbonate mean?
A 1M solution of sodium carbonate contains 1 gram formula mass of sodium carbonate dissolved in each liter of solution.
How much sodium chloride is required to make 1litre of 1M solution?
0.056g
What is the make up of 0.1 sodium hydroxide?
20 grams of NaOH in 1000 ml water(1M)
What is the conductivity of 1M NaOH?
What is the conductivity of 1 molar solution of sodium hydroxide at ambient temperature
How do you prepare a solution containing 300ml of 1M Sodium Sulfate?
That is a poorly worded question. The way you have worded it could be answered correctly by instructing you to "Pour 300ml of 1M solution in a swimming pool."The question is usually posed in the form of "How much sodium sulfate is needed to produce 300 ml of 1M solution?" Presuming you intend the latter, you would prepare 300 ml of 1M solution by mixing 300/1000 of a mole of sodium sulfate with sufficient water to produce 300 ml of solution.Note the difference between Molar and Molal: 1M = 1 mole per liter of solution, 1 molal = 1 mole per liter of water. This distinction has a major effect on the wording of your answer.300 ml / 1000 ml = 3/10 = 0.3000One mole of sodium sulfate (Na2SO4) has the formula weight of 142.04314 g/mol as shown below:fw Na x 2 = 22.98977 g/mol x 2 = 45.97954 g/molfw S = 32.066 g/molfw O x 4 = 15.994 g/mol x 4 = 63.9976 g/mol45.97954 g/mol + 32.066 g/mol + 63.9976 g/mol = 142.04314 g/molThe mass of 0.3000 mol x 142.04314 g/mol = 42.613 g.Note: The final answer was rounded to the thousandths place because the formula weight for Sulfur was the least precise term.
What does 1M solution of sodium carbonate mean?
A 1M solution of sodium carbonate contains 1 gram formula mass of sodium carbonate dissolved in each liter of solution.
How can we prepare 1M solution of NaCl?
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
How to prepare 1m hcl from 35 percent hcl?
10.82
How do you prepare 10mM Tris?
Dilute 1M Tris 1:100
Which phase will be on top in an immiscible mixture of methylene chloride and 1M of sodium hydroxide?
Sodium hydroxide solution will be on the top.
How much sodium chloride is required to make 1litre of 1M solution?
0.056g
What is produced at the cathode of an electrolytic cell containing 1M solution of sodium chloride?
Chlorine gas. Cl2
What is the make up of 0.1 sodium hydroxide?
20 grams of NaOH in 1000 ml water(1M)
What is 1m x 1m x 0.5m?
1m*1m*0.5m=0.5m3
What is the conductivity of 1M NaOH?
What is the conductivity of 1 molar solution of sodium hydroxide at ambient temperature
What amount of NaOH is required to prepare 1N NaOH solution and why only that amount is used?
40 grams, this is the 1M NaOH standard laboratory solution.
How do you prepare a solution containing 300ml of 1M Sodium Sulfate?
That is a poorly worded question. The way you have worded it could be answered correctly by instructing you to "Pour 300ml of 1M solution in a swimming pool."The question is usually posed in the form of "How much sodium sulfate is needed to produce 300 ml of 1M solution?" Presuming you intend the latter, you would prepare 300 ml of 1M solution by mixing 300/1000 of a mole of sodium sulfate with sufficient water to produce 300 ml of solution.Note the difference between Molar and Molal: 1M = 1 mole per liter of solution, 1 molal = 1 mole per liter of water. This distinction has a major effect on the wording of your answer.300 ml / 1000 ml = 3/10 = 0.3000One mole of sodium sulfate (Na2SO4) has the formula weight of 142.04314 g/mol as shown below:fw Na x 2 = 22.98977 g/mol x 2 = 45.97954 g/molfw S = 32.066 g/molfw O x 4 = 15.994 g/mol x 4 = 63.9976 g/mol45.97954 g/mol + 32.066 g/mol + 63.9976 g/mol = 142.04314 g/molThe mass of 0.3000 mol x 142.04314 g/mol = 42.613 g.Note: The final answer was rounded to the thousandths place because the formula weight for Sulfur was the least precise term.
