Hydrochloric acid is prepared by dissolving hydrogen chloride gas in water. Hydrogen chloride is a covalent compound, but when dissolved in water it ionizes to form hydrogen ions and chloride ions as follows: By Kuldeep K. bansal India
no-AH
6g Tris HCl + 100ml dH2O, pH 6.8
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
25 mL
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.
no-AH
6g Tris HCl + 100ml dH2O, pH 6.8
520 ml of HCl in 480 ml of water=1000ml = 5 N
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
25 mL
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.
Mix approx. 12 mL of HCl 30 % in 1 L water.
To calculate the number of milliliters (mL) of hydrochloric acid (HCl) required to prepare a standard solution of 2 mols of HCl, we need to know the concentration of the available HCl solution. The calculation involves the following steps: Determine the number of moles of HCl desired in the solution. Given: 2 mols of HCl Determine the concentration (molarity) of the available HCl solution. Let's assume the concentration is 6 M (This is a common concentration for laboratory-grade HCl, but you should use the actual concentration of your solution). Use the molarity equation to calculate the required volume (in liters): Molarity (M) = moles of solute / liters of solution 6 M = 2 mols / liters of solution Liters of solution = 2 mols / 6 M Liters of solution = 0.333 L Convert the volume from liters to milliliters: Volume in mL = Volume in liters × 1000 mL/L Volume in mL = 0.333 L × 1000 mL/L Volume in mL = 333 mL Therefore, to prepare a standard solution of 2 mols of HCl using a 6 M HCl solution, you would need approximately 333 mL of the concentrated HCl solution. Note: The actual volume may vary slightly depending on the precise concentration of the HCl solution you are using and any significant figures involved in the calculation.
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
add 5 ml of 37% HCl to 495 ml Water. This is 0.12 N ;)
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION