answersLogoWhite

0


Best Answer

Hydrochloric acid is prepared by dissolving hydrogen chloride gas in water. Hydrogen chloride is a covalent compound, but when dissolved in water it ionizes to form hydrogen ions and chloride ions as follows: By Kuldeep K. bansal India

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you prepare HCL solution in Laboratory?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How do you prepare NaOH solution in laboratory?

no-AH


How do you prepare tris-hcl buffer solution of 0.5M?

6g Tris HCl + 100ml dH2O, pH 6.8


How do you prepare 5N hcl solution?

520 ml of HCl in 480 ml of water=1000ml = 5 N


How to prepare HCL solution?

Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter


What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?

25 mL


How do you prepare 10mM solution of Tris-HCl?

1.21 g Tris-HCl, QS water to 1L. Scale appropriately.


How do you prepare N by10 HCl solution?

Mix approx. 12 mL of HCl 30 % in 1 L water.


How many miles of HCl will be required to prepare a standard solution of 2mols of HCl?

To calculate the number of milliliters (mL) of hydrochloric acid (HCl) required to prepare a standard solution of 2 mols of HCl, we need to know the concentration of the available HCl solution. The calculation involves the following steps: Determine the number of moles of HCl desired in the solution. Given: 2 mols of HCl Determine the concentration (molarity) of the available HCl solution. Let's assume the concentration is 6 M (This is a common concentration for laboratory-grade HCl, but you should use the actual concentration of your solution). Use the molarity equation to calculate the required volume (in liters): Molarity (M) = moles of solute / liters of solution 6 M = 2 mols / liters of solution Liters of solution = 2 mols / 6 M Liters of solution = 0.333 L Convert the volume from liters to milliliters: Volume in mL = Volume in liters × 1000 mL/L Volume in mL = 0.333 L × 1000 mL/L Volume in mL = 333 mL Therefore, to prepare a standard solution of 2 mols of HCl using a 6 M HCl solution, you would need approximately 333 mL of the concentrated HCl solution. Note: The actual volume may vary slightly depending on the precise concentration of the HCl solution you are using and any significant figures involved in the calculation.


How can you prepare several different pH solutions from a 1 Molar stock solution of HCl?

dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html


Prepare 500ml of 0.12N HCL solution?

add 5 ml of 37% HCl to 495 ml Water. This is 0.12 N ;)


You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml?

Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.


How many mL of HCL do you measure to prepare a liter of 0.5N HCL?

44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION