Mazda Protege

How do you remove the EGR valve on a 99 Mazda protege 1.8L?

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2012-04-25 16:33:29
2012-04-25 16:33:29

Were is the egr valve on a 99 Mazda progege 1.8

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18L per 100km equates to 13 miles per gallon!


Since there are 1000ml in a L, that would be 18,000.


18L is 4.76 US gallons.


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18000mL is 18L (divide mL by 1,000).1800 ml = 1. 8 liter


Use the radio's volume and frequesce setting buttons next to the clock.


1800 mL. There is 1000 mL in 1L. To get the answer, multiply 18L by 1000 and you'll get 1800 mL.


only 1 small gold fish but they really should be cept in an 18l tank or more


I found this site, http://installdr.com/InstallDocs/Acura/Integra.html, hope it helps.


there is no difference unless you are referring to the Northrop Grumman F-18L and the McDonnell Douglas F/A-18



The width of the room is equal to twice the Length. Suppose Length = L, width = W, and A = areaW = 2L from the information in the questionNow we know area, A is equal to length times widthW*L=A, plug in 2L for W and we get 2L*L=A or 2L^2=ANext, we see that when 6 is subtracted from both length and width A becomes 108 less.So (2L-6)*(L-6)=A-108Multiply (2L-6)*(L-6) out and the result is (2L^2-18L+36) Set that equal to A-108(2L^2-18L+36)=A-108. We found out that A=2L^2 earlier so we can substitute the terms.(2L^2-18L+36)=2L^2-108. Now solve for LSubtract 2L^2 from both sides(-18L+36)=(-108)Subtract 36 from both sides(-18L)=(-144)Divide by (-18)L=8We know W=2L so W=16Now lets test our answer.16*8=128(16-6)*(8-6)=10*2=20128-20=108So the answer of L=8 and W=16 is correct.


The F-18 was based on the YF-17 (the aircraft that "lost" the USAF LWF [Lightweight Fighter Program] ). The YF-17 was a development of the P-530 Cobra (which, in turn, was a roundabout development of the F-5 Freedom Fighter). All of these aircraft were a product of Northrop, with McDonnell-Douglas providing much input at the stage between YF-17 and F-18 as completed. The agreement between the two firms was that MDD would produce the naval variants (F-18, which became the F/A-18) and Northrop would produce the land-based versions (F-18L). Unfortunately for Northrop there were no orders for the F-18L.


The bypass hose is a pain in the butt to replace. requires access from top and bottom, about an hour and the patience of a saint. I cut the old clamps off with cutters to speed removal, installation is still a pain...



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The best solution is to purchase and install a clamp on block heater which is available through a Suzuki dealer. To my knowledge, you can't install a normal type of block heater (installs in frost plug). Dave Saskatchewan Canada 96 Suzuki Sidekick Sport


It takes an experienced mechanic about three hours to change from start to finish. You may be able to find a good used turbo for about $400, the new gaskets will be about $80. A new turbo is around $900. Check rockauto.com for good parts prices, I've had good luck there, also vwvortex.com


The Jetta engine should fitAnswerAny four-cylinder watercooled VW engine will FIT in the car; every watercooled inline-4 Volkswagen engine has the same bellhousing pattern and mounting bolt hole locations. The question is, which engines will work? And really, because of all the electronics in your car I wouldn't guarantee anything but another 1.8 Turbo would work.


The figure could be a rectangle with length 6.79 and width 2.21(2dp). Area (A) of a rectangle = Length (L) x Width (W) = 15 : Then W = 15/L Perimeter = 2(L + W) = 18 : substituting for W then :- 2(L + 15/L) = 18 : 2L + 30/L = 18 : 2L2 - 18L + 30 = 0 Solving for a quadratic equation gives L = (18 ± √84) ÷ 4 = 4.5 ± √5.25 = 4.5 ± 2.29(2dp)


Let L be the length of the rectangle. Since the length of the side of the square is the same as the width of the rectangle and the width of the rectangle is its length minus 6, the length of the side of the square is (L-6) and the area is (L-6)2. Since the width of the rectangle is its length minus 6, its area is L(L-6). Here is some of the work: 176 = (L-6)2 + L(L-6) 176 = (L-6)(L-6) + L(L-6) 176 = L2 - 6L - 6L + 36 + L2 - 6L 176 = 2L2 - 18L + 36 140 = 2L2 - 18L 70 = L2 - 9L 70/L = L - 9 (9L + 70)/L = L L = (9L+70)/L L2 = (9L+70) L = sqrt(9L+70) According to WolframAlpha (www.wolframalpha.com), L=14. (But don't say L; use x). The length of the side of the square is 8 m, which is also the width of the rectangle; the length of the rectangle is 14 m; the area of the square is 64 m2; and the area of the rectangle is 112 m2.


Let w equal the width and l equal the length of the rectangle. This means that 2w+2l=135 and since the rectangle has a scale factor of 8:1, that w/l=8. We now have a system of equations. Solve the second equation for w and find that w=8l. Substitute this into the first equation and find that 2(8l)+2l=135, which simplifies to 18l=135. Solve for l to get l=7.5 units. Plug this into either of the original equations to find that w=60 units. The dimensions of the rectangle are 60 by 7.5 units.


it should last between 150,000 and 200,000 miles... mine just went out at 155,000... the implications... depends on what happened... if it seizes... then you will create no boost... and you'll have excess back pressure... if the oil bushing goes out... it'll slip to an angle... and machine the inside of the housing... or it'll just disintigrate... best thing you can do to prevent this... is just use synthetic blend oil... unless its been brought up on full synthetic... I know it costs more... but its worth it... and don't go more than 3000 miles before an oil change... don't go with the dealer recommended 5000...



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