Draw a sine wave, except that when it wants to go negative, keep it at zero instead.
When alternating current of any frequency is fully rectified, both halves of the wave are converted to direct current and utilized. Half-wave rectification is when half of the wave is ignored. So the main characteristic that is changed is the shape of wave by flipping half the wave over to the same side as the rest. But it does not flatten the peaks on the wave without additional filtering.
A pool pump motor which is drawing half the amps listed on its nameplate can indicate a problem with the windings or a lack of incoming current. Pumps will only draw as many amps as are required to operate under the current load.
The maximum current output of a CT is 5 amps. Connected to a meter this will be full scale. What ever the ratio of the CT will dictate the scale face on the meter. A 500 amp CT's output will be 5 amps at 500 amps on the buss. 250 amps on the buss, the CT will output 2.5 amp or half scale on the meter face.
Volts and amps measure two different things. Volts are used to measure potential difference. Amperes (amps for short) are used to measure current. Compare it to a garden hosepipe: Voltage corresponds to the pressure of the water, current measures how fast the water flows. 2000 millivolts equals two volts. For comparison, a single AA cell gives 1.5 volts. 1000 amps is several times the current used by the average household. A regular AA cell can provide, at maximum, about half an amp.
Watts = current x volts for a resistive load. You need to know a voltage to calculate amps. If it is a 120 VAC residential voltage it would be a whopping 266,000/120 = A or 2,216.7 Amps. If it is 240 VAC then half that. To put that in perspective the service to a typical residence might be between 100 and 200 Amps.
It is smoothing
You need to know amps to answer this... Amps x Volts=watts
rms value of voltage
Half that, or 2 amps. The basic rule in circuits is that voltage (E) equals current (I) times resistance (R). Here's how that expression of Ohm's law looks: E= I x R That means that current equals voltage divided by resistance, as is shown here: I = E / R This expression says that resistance is inversely proportional to current (with voltage staying the same). Further, if resistance goes up, current goes down. If resistance doubles (goes up by a factor of 2), which it does in the case specified in the question, then current is cut in half (goes down by a factor of 2). Half of 4 amps is 2 amps, and that's where the answer came from.
In case of bridge rectifier we have diodes D1, D3 are in parrallel limbs and D2 and D4 in another parallel limb For first half cycle, D1, resistance (load) and D3 would be the path for the current to flow For the second half cycle D2, load and D4 would be the passage for the flow of current. But in both the half cycles current seems flowing through the load in the same direction. Hence direct current. Thus the AC has been rectified into DC. Bridge rectifier has an efficiency 81.2%
The diode is a unidirectional device it allows current to pass through it only when it is forward biased and does not allow when reverse biased when ac signal is supplied in the positive half cycle of the ac wave signal the diode will b in forward biase n in the negative half cycle it is in reverse bias .Hence it allows only the positive half cycle current to flow through it the resultant wave form will b only in one direction ,i.e,dc signal with ripples. only half of the wave is rectified hence it acts as a half wave rectifier
It's hard to define a sound, but here's a try: A half-wave rectified sine sounds harsh and whiney. Not as sharp and jagged as a square wave, but not nearly as pure and smooth as a sine. The key is to realize that the half-wave rectified sine is a sine plus a significant load of harmonics, and wherever there is a lot of harmonic energy, we call it "total harmonic distortion". So the bottom line is, anything that isn't a pure sine, you would say it sounds "distorted".