0
How do you solve a 200-lb crate lies on the floor. The coefficient of static friction between the crate and the floor is 0.60. What is the minimum force required to start the crate sliding?
Wiki User
∙ 6y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
What is the minimum force required to pull a 50 kg bag of fertilizer across the floor if the coefficient of friction is 0.37?
The formula for friction is Fr = μR Where μ is the coefficient of friction, and R is the normal contact force. So the normal contact force will be Mass x gravity = 50*9.81 = 490.5 0.37 * 490.5 = 181.485 N It is worth noting that that answer is too precise and also that I ignored the vectors and just used magnitude, in more difficult problems you will need to use vectors.
What are the factors which affect the coefficient of static friction?
Dry surfacesFor low surface pressures the friction is directly proportional to the pressure between the surfaces. As the pressure rises the friction factor rises slightly. At very high pressure the friction factor then quickly increases to seizingFor low surface pressures the coefficient of friction is independent of surface area.At low velocities the friction is independent of the relative surface velocity. At higher velocities the coefficent of friction decreases.Well lubricated surfacesThe friction resistance is almost independent of the specific pressure between the surfaces.At low pressures the friction varies directly as the relative surface speedAt high pressures the friction is high at low velocities falling as the velocity increases to a minimum at about 0,6m/s. The friction then rises in proportion the velocity 2.The friction is not so dependent of the surface materialsThe friction is related to the temperature which affects the viscosity of the lubricant
A body of mass 10 kg is lying on a horizental surface if the cofficient of friction between the body and the surface is 0.2 then answe the following questions1what is the minimum force required to Sli?
The limiting friction is given by the expression Mu R. Here mu is the coefficient of friction and 0.2 is the value given as the data. R is the reaction which equal to mg where m is the mass and here it is 10 kg and g is 9.8 m/s^2 Hence the limiting friction = 0.2 x 10 x 9.8 = 19.6 N. A force of 19.6 N is enough to make the body to slip
What is range of reflection coefficient?
The magnitude of the reflection coefficient lies in the range of .
What is force energy?
The minimum energy required for molecules to react.
A solid homogenous sphere rolls without slipping down a plane that makes an angle of 30 degree with the horizontal find the linear acceleration of the sphere and the minimum coefficient of friction?
There is no minimum value for the coefficient of friction. And the linear acceleration will depend on its unknown value.
What is the minimum rate of flow at which a stream of water can maintain the transportation of 1.0 centimeters in diameter?
You would have to know the weight or density of the pebbles, the coefficient of friction on the pebble's surface and the coefficient of friction on the ground.
What is the maximun coefficient of friction between two surfaces?
friction is the resisting force which oppose the relative motion of two body.cofficient of friction is the ratio of frictional force and normal force of body on surface.thus maximum cofficient of friction defiend as ratio of maximum frictional force or minimum normal force on the surface.
What is the minimum force required to pull a 50 kg bag of fertilizer across the floor if the coefficient of friction is 0.37?
The formula for friction is Fr = μR Where μ is the coefficient of friction, and R is the normal contact force. So the normal contact force will be Mass x gravity = 50*9.81 = 490.5 0.37 * 490.5 = 181.485 N It is worth noting that that answer is too precise and also that I ignored the vectors and just used magnitude, in more difficult problems you will need to use vectors.
How do you find the minimum coefficient of static friction for a mass on an incline of 32 degrees?
The equation for friction is F=uN. F (friction), u (coefficient of friction), and N (normal). So you first need to solve for the normal by using Newton's second law. Also solve for the x component of the gravity force. Since it is static friction, you know it should be at rest, so that x component force should be the same as the force of friction. Knowing that and the normal, plug it into the equation and solve for u.
What are the factors which affect the coefficient of static friction?
Dry surfacesFor low surface pressures the friction is directly proportional to the pressure between the surfaces. As the pressure rises the friction factor rises slightly. At very high pressure the friction factor then quickly increases to seizingFor low surface pressures the coefficient of friction is independent of surface area.At low velocities the friction is independent of the relative surface velocity. At higher velocities the coefficent of friction decreases.Well lubricated surfacesThe friction resistance is almost independent of the specific pressure between the surfaces.At low pressures the friction varies directly as the relative surface speedAt high pressures the friction is high at low velocities falling as the velocity increases to a minimum at about 0,6m/s. The friction then rises in proportion the velocity 2.The friction is not so dependent of the surface materialsThe friction is related to the temperature which affects the viscosity of the lubricant
How much minimum torque is required by a turbine to generate Electricity?
initial torque to overcome the friction in generator and then to keep constant speed of stator within the generator. Minimum 50NM
A body of mass 10 kg is lying on a horizental surface if the cofficient of friction between the body and the surface is 0.2 then answe the following questions1what is the minimum force required to Sli?
The limiting friction is given by the expression Mu R. Here mu is the coefficient of friction and 0.2 is the value given as the data. R is the reaction which equal to mg where m is the mass and here it is 10 kg and g is 9.8 m/s^2 Hence the limiting friction = 0.2 x 10 x 9.8 = 19.6 N. A force of 19.6 N is enough to make the body to slip
What is the function of a bearing?
To bear a load between two moving parts with the minimum amount of friction
How does teflon reduce friction?
it creates a easy layer between two objects causing them to have no friction. friction means two objects rubbing against each other. Teflon reduces the "rubbing" so to speak to a minimum by putting a slippery coat in between and in turn creating no friction.
How is friction between bones kept to a minimum?
synovial fluid Plus the cartridge on the ends of the bones in a movable joint.
What is range of reflection coefficient?
The magnitude of the reflection coefficient lies in the range of .
