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Q: How do you solve a 200-lb crate lies on the floor. The coefficient of static friction between the crate and the floor is 0.60. What is the minimum force required to start the crate sliding?

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The formula for friction is Fr = μR Where μ is the coefficient of friction, and R is the normal contact force. So the normal contact force will be Mass x gravity = 50*9.81 = 490.5 0.37 * 490.5 = 181.485 N It is worth noting that that answer is too precise and also that I ignored the vectors and just used magnitude, in more difficult problems you will need to use vectors.

Dry surfacesFor low surface pressures the friction is directly proportional to the pressure between the surfaces. As the pressure rises the friction factor rises slightly. At very high pressure the friction factor then quickly increases to seizingFor low surface pressures the coefficient of friction is independent of surface area.At low velocities the friction is independent of the relative surface velocity. At higher velocities the coefficent of friction decreases.Well lubricated surfacesThe friction resistance is almost independent of the specific pressure between the surfaces.At low pressures the friction varies directly as the relative surface speedAt high pressures the friction is high at low velocities falling as the velocity increases to a minimum at about 0,6m/s. The friction then rises in proportion the velocity 2.The friction is not so dependent of the surface materialsThe friction is related to the temperature which affects the viscosity of the lubricant

The limiting friction is given by the expression Mu R. Here mu is the coefficient of friction and 0.2 is the value given as the data. R is the reaction which equal to mg where m is the mass and here it is 10 kg and g is 9.8 m/s^2 Hence the limiting friction = 0.2 x 10 x 9.8 = 19.6 N. A force of 19.6 N is enough to make the body to slip

The magnitude of the reflection coefficient lies in the range of .

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You would have to know the weight or density of the pebbles, the coefficient of friction on the pebble's surface and the coefficient of friction on the ground.

friction is the resisting force which oppose the relative motion of two body.cofficient of friction is the ratio of frictional force and normal force of body on surface.thus maximum cofficient of friction defiend as ratio of maximum frictional force or minimum normal force on the surface.

The formula for friction is Fr = μR Where μ is the coefficient of friction, and R is the normal contact force. So the normal contact force will be Mass x gravity = 50*9.81 = 490.5 0.37 * 490.5 = 181.485 N It is worth noting that that answer is too precise and also that I ignored the vectors and just used magnitude, in more difficult problems you will need to use vectors.

The equation for friction is F=uN. F (friction), u (coefficient of friction), and N (normal). So you first need to solve for the normal by using Newton's second law. Also solve for the x component of the gravity force. Since it is static friction, you know it should be at rest, so that x component force should be the same as the force of friction. Knowing that and the normal, plug it into the equation and solve for u.

Dry surfacesFor low surface pressures the friction is directly proportional to the pressure between the surfaces. As the pressure rises the friction factor rises slightly. At very high pressure the friction factor then quickly increases to seizingFor low surface pressures the coefficient of friction is independent of surface area.At low velocities the friction is independent of the relative surface velocity. At higher velocities the coefficent of friction decreases.Well lubricated surfacesThe friction resistance is almost independent of the specific pressure between the surfaces.At low pressures the friction varies directly as the relative surface speedAt high pressures the friction is high at low velocities falling as the velocity increases to a minimum at about 0,6m/s. The friction then rises in proportion the velocity 2.The friction is not so dependent of the surface materialsThe friction is related to the temperature which affects the viscosity of the lubricant

initial torque to overcome the friction in generator and then to keep constant speed of stator within the generator. Minimum 50NM

The limiting friction is given by the expression Mu R. Here mu is the coefficient of friction and 0.2 is the value given as the data. R is the reaction which equal to mg where m is the mass and here it is 10 kg and g is 9.8 m/s^2 Hence the limiting friction = 0.2 x 10 x 9.8 = 19.6 N. A force of 19.6 N is enough to make the body to slip

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it creates a easy layer between two objects causing them to have no friction. friction means two objects rubbing against each other. Teflon reduces the "rubbing" so to speak to a minimum by putting a slippery coat in between and in turn creating no friction.

synovial fluid Plus the cartridge on the ends of the bones in a movable joint.

The magnitude of the reflection coefficient lies in the range of .