Calculating the freezing point depression of a solvent requires three pieces of information: 1) the molal freezing point depression of that solvent; 2) the molality of the solution; 3) the number of distinct entities produced in solution per molecular formula unit of solute. Hopefully you meant molality instead of molarity (if the solvent is water and it's a dilute solution, assuming that molality = molarity isn't a bad approximation). I suspect you've been told what 1 and 3 are (or been given enough information to figure them out) but simply didn't mention it; otherwise you're pretty much boned.
Substances which are insoluble in a given solvent do not cause a freezing point depression in that solvent.
Molarity is the no of moles of solute dissolved per litre of a solution. now if u want to find it from the percentage purity , here is the formula for that Molarity = % purity x density x 10 ___________________ molar weight of the solute note : density is usually given %purity problems, if its not u can evualvate it from from formula { d= mass/volume} i hope it solves the problem
Modernism (A+)
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The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.
Modernism :)
Modernism
Modernism :)
Modernism :)
Modernism :)
The molarity of a solution is the amount of substance in a given amount of solute. The units are usually given as moles per liter (or dm3). As such, for each liter you have 0.5 moles of substance (2 divided by 4), so it's a 0.5 molar solution.
You know the molarity and you know the volume. First off you find the moles. Molarity divided by 1000, multiplied by the volume in cm^3. Then you multiply the moles by the molecular mass of the solute, to get the weight in grams.