2Na + 2H2O = 2NaOH + H2
Equations like this are always solved by simultaneous equations using 1Na +xH2O = aNaOH + bH2 which gives
1=a from Na
2x=a+2b from H
x=a from O
so x=1, b=0.5 then multiply the whole equation by 2 to get whole numbers without upsetting the balance.
precipitation reactions are one way to deter what ions are present in a reaction for example sodium hydroxide reacts with metal ions like copper, it will then form a blue/green precipitate which is an insoluble solid - copper hydroxide - so you would know that copper ions are present in the solution
In short just use algebra to get the equation below Start with [P + a*(n/V)^2] * (V - nb) = nRT which is the standard Van Der Waals equation and solve for n using algebra. which gives the 3rd order equation below. -(ab/V^2)*n^3 + (a/V)*n^2 - (bP+RT)*n + PV = 0 The simplest way to solve this equation is to enter it into Excel and graph it with multible values of n from 0 to whatever gets you to zero. The value that gives you zero is the answer. Be sure you use all the proper units for the other varables. Hope this helps.
Because chemical reactions take place in molar ratios. The number of moles of each kind of atom has to be the same on both sides of the equation.
It is SF6 but i don't know how you would represent the chemical bonding formula and how you would solve it. its a tricky one.
This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles. Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
you don't answer an equation, you solve an equation
solve it
If you solve such an equation for "y", you get an equation in the slope-intercept form.
It is not an equation if it does not have an equals sign. You could simplify it but not solve it.
How do you use division to solve a multiplication equation?Answer this question…
you can only solve for one in an equation so it can equal something
There is no such thing as "solving integers". You can solve an equation, which means finding all the unknowns in that equation, but you can't solve an integer.
it is not an equation (there no equality in it!)
Every equation has a solution.
Please solve this equation.
You solve the equation.