First off, if you have 24 in 500ml, you have 48g in 1 litre. Now you need to divide by molecular weight. 48/81 is 0.5926 molar. Though I'm not sure if that compound exists.
M1
Proteins are solute molecules found in a dissolved form in buffer. Proteins can be crystallized to form a crystal (solid) by evaporation. This method is used in protein X-ray crystallography to solve its 3D structure.
For a weak acid, HA...HA ==> H^+ + A^- Ka = [H+][A-]/[HA] Plug these values into the Ka equation. You also must know the [HA] that you start with. Solve for [H+] Take -log [H+] = pH
she was trying to solve how the animals were living.
The most easiest method to solve trigonometric problems is to be place the values of the sin/cos/tan/cot/sec/cosec . The values will help to solve the trigonometric problems with less difficulty.
M1
Given: 0.5 g NaCl; 0.05 L of solution.1) Find the molar mass of NaCl.(22.99) + (35.45) = 58.44 g/mol of NaCl2) Convert grams of NaCl to moles of NaCl.(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl3) Use the molarity equation, M = mol / L, to solve for molarity (M).(0.00855578 mol NaCl / 0.05 L) = 0.17 M
Dissolved rhymes with "resolved". Hope that helps!
Using this ideal gas equation PV=nRT. The question provided the following: P=2.61 atm V=2.14L R=0.0821 ( this is standard for any ideal gas) T= 28 C+273K= 301 n= unknown Since there is no volume change, so the volume is constant from the beginning of the reaction to the the end of the reaction. The only key information we are missing is the actual number of moles (n). We must rearrange the ideal gas equation to solve for moles. n=PV/RT n=(2.61)(2.14)/(.0821)(301) n=.2260 The question wants us to find the Molarity of the acid solution. We were given that HCL completely dissolved in 668mL of water. Molarity moles/Liters. 668mL=.668L M=.2260mol/.668L so Molarity of the acidic solution is .338.
pure substances have a molarity of 1. but, if you need a calculation, you could start with the definition of molarity (M) is grams of solute/molar mass of solute x liters of solution, there is some missing information for this problem to be solved as a solution but with a conversion factor, you should be able to find an answer. Moles (n) can be calculated as follows: 68.7 g Pb (n/207.1g) = .332 mol Pb 117 g Sn (n/118.7g) = .989 mol Sn density: d = m/v = g/mL lead 11.34  g·cm−3 tin 7.31 g/ml these conversions can be put into the analysis equation and should be able to solve.
with the steps
186g C6H12O6 Use a concentration formula. Molarity - moles of solute/liters of solution. molarity = 1 moles of solute= x liters= 1 solve the equation and x= 1. One mole of glucose is equal to 186 grams.
No, this cannot be answered. This is explained below:Please remember thatdensity is in g / mL (gram per millilitre)and molar mass is in g / mol (grams per mole)and molarity is in mol / mL (moles per millilitre)Without molar mass (in g/mol) molarity cannot be calculated from just knowing it is an triglyceride with density 0.91 g/mL (which is of no significance for this question, many trig's have a comparable density).
In the scientific sense, the term dissolve means to mix into a liquid, typically forming a homogeneous solution. This is different from the process of melting. Melting defines a phase change, where a chemical substance changes state from the solid to the liquid form.
Calculating the freezing point depression of a solvent requires three pieces of information: 1) the molal freezing point depression of that solvent; 2) the molality of the solution; 3) the number of distinct entities produced in solution per molecular formula unit of solute. Hopefully you meant molality instead of molarity (if the solvent is water and it's a dilute solution, assuming that molality = molarity isn't a bad approximation). I suspect you've been told what 1 and 3 are (or been given enough information to figure them out) but simply didn't mention it; otherwise you're pretty much boned.
Proteins are solute molecules found in a dissolved form in buffer. Proteins can be crystallized to form a crystal (solid) by evaporation. This method is used in protein X-ray crystallography to solve its 3D structure.
For a weak acid, HA...HA ==> H^+ + A^- Ka = [H+][A-]/[HA] Plug these values into the Ka equation. You also must know the [HA] that you start with. Solve for [H+] Take -log [H+] = pH