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Oh ya you Bettye!
I have a Winchester Model 240W Westernfield "12 ga." (not 20ga.) shotgun. It was a knockoff of the Winchester model 1400, made for Montgomery Wards. I've seen them sell anywhere between $200 and $250 depending on condition.
I bought one new from Montgomery Wards about 25 years ago
Depends on the speakers. Usually something like 60W RMS, 240W Peak.
I think the numbers should both be voltages, if so, absolutely not.
Without a maker's name, can't be answered. Even then, ther may be no info.
It mainly has 10W,20W,30W,50W,60W,80W,100W,120W,150W,180W,210W,240W,300W,360W.
I think you mean a 240 V to 110 V (volts, not watts) transformer! Providing your power tool is rated at 110 V, the answer is yes, because its power rating of 1500 W is well within the capacity of a 3-kV.A transformer.
based on the load,your battery back up may determined.for 600va inverter u can provide a maximum load of 460w(app.)for fan its 80w and tubelight it's 40w.if your using 100ah battery,your backup for running the 2 fans and 2 light have load upto 240w is 5hours(app.).duration may differs based on the efficiency of the battery
120 x 36 = 4320w which is 4.32kw. in England to run these lights for 1 hour would cost you approx 45 pence. 120 x 2 = 240w which is 0.25w. to run 120 led spot lights for 1 hour would cost you approx 2.5 pence. so the saving is quite vast. dean burnley
The effective resistance of three resistors, 120 ohm, 60 ohm, and 40 ohm, in parallel is 20 ohms.RP = 1 / sum (1 / RN)RP = 1 / (1 / 120 + 1 / 60 + 1 / 40)RP = 20The voltage applied, 120V, does not change the outcome. The power, however, of the three resistors is 120W, 240W, and 360W respectively. This is a lot of power, so please do not attempt to do it for real.
The Ampere-Hour rating tells you how much energy can be extracted from a given battery. For our 30AH battery, you could draw 1A for 30 hours, 2A for 15 hours, 3A for 10 hours, 30A for 1 hour, or any combination where Amps X hours = 30, within reason. Are you talking about a battery supplying a load directly, like a 12V battery supplying a 240W, 12V heater? Or do you mean a battery running an inverter supplying a 120V, 240W load? For the direct load, first calculate Amps drawn by the load. Amps = Watts / Volts. Then divide the A/H rating of the battery by the load Amps. Example: * 240W, 12V heater * Amps = 240 / 12 = 20A * Time = 30AH / 20A = 1.5 hours (90 minutes) For a load run by invertor, you just divide the Watts needed by the efficiency of the invertor. The efficiency rating is almost always found on the nameplate or in the manual. Most modern invertors are in the range of 90% - 96%. Example: * Same as above, except load is 120V, 240W heater run through a 90% efficient invertor. * Watts drawn from battery = 240 / 0.9 = 267 W * Amps = 267 / 12 = 22.2A * Time = 30AH / 22.2A = 1.35 hours (81 minutes) One factor to consider: The Amp-Hour rating of a battery is only valid up to about 10% of capacity current draw. So, a 30AH battery is only 30AH for loads up to 3A. At very high loads, the available AH from a battery decreases. This derating varies with size and manufacturer, but don't count on getting every minute of operation from our example above, because our current draw is much higher than 3A. In this case we might only have 25AH or so to play with.