You can reverse a number by extracting its digits (num%10) and then appending these digits to a new variable. Here is the code:
int num, revnum = 0, temp;//revnum stored the reversed number
scanf("%d", &num);//The number to be reversed
temp = num;
while( temp != 0){
revnum = revnum*10 + temp%10;
temp /= 10;
}
printf("The reversed number is :%d\n", revnum);
The use of the reverse string in C program is used to reverse the letters in the string. An example would be reverse me would be reversed to em esrever.
Reference:cprogramming-bd.com/c_page2.aspx# reverse number
To check if a number is a palindrome, reverse the number and see if it is equal to the original number. If so, the number is a palindrome, otherwise it is not. To reverse a number, use the following function: int reverse(int num, int base=10) { int reverse=0; while( num ) { reverse*=base; reverse+=num%base; num/=base; } return(reverse); }
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
You can get the answer in the following link : http://www.dreamincode.net/forums/showtopic27453.htm
Reverse the digits then check of the new number is the same as the original number.
The C-130 does not have a speed brake. They use a combination of brakes, flaps, and reverse thrust to slow down.
//Reverse of the Number // Programme Written By Maulin Thaker Ahmedabad; #include<stdio.h> #include<conio.h> void main() { int a,b,c,d,e; clrscr(); printf("Enter the Number to Find it's Reverse\n"); scanf("%d",&a); while(a!=0) { b=a%10; c=a/10; printf("%d",b); a=c; } getch(); }
I'd use sprintf (assuming the number wasn't a string already) and pointers. If that's not enough of a clue, you're really not ready to be in this programming class.
/*Reverse the digits of a number,Gankidi*/ #include<stdio.h> void main(void) { int num,sum=0,i,rem; printf("Enter a number"); scanf("%d",&num); while(num>0) { rem=num%10; num=num/10; sum=sum+(rem*10); } printf("the reverse number is %d",sum); }
#include <stdio.h> #include<conio.h> void main () { int a,r,n,sum=0; clrscr(); printf("enter the number"); scanf("%d",& n); c=n while (n!=0) { a=n%10; n=n/10; sum=sum*a+a } printf("the reverse is %d \n",sum); if(c==sum) printf("\n the given number is palindrome"); else printf("\n the given number is not a palindrome"); getch(); }
let a, b, c denote the three digits of the original number, then the three-digit number is 100a+10b+c. The reverse is 100c+10b+a. Subtract: (100a+10b+c)-(100c+10b+a) to get 99(a-c). Since the digits were decreasing, (a-c) is at least 2 and no greater than 9, so the result must be one of 198, 297, 396, 495, 594, 693, 792, or 891. When you add any one of those numbers to the reverse of itself, you get 1089